Solving for Tangent Lines: Analytical and Graphical Approaches

  • Thread starter Thread starter brochesspro
  • Start date Start date
  • Tags Tags
    Lines Tangent
brochesspro
Messages
155
Reaction score
22
Homework Statement
Find the equations of the two lines through the point ##(3, 1)## that are tangent to the curve ##y = x^2 - 4##. Hint: Draw the graph, let ##(a, a^2 - 4)## be the point of tangency, and find ##a##.
Relevant Equations
Given below.
1641411415668.png

I did it graphically by using GeoGebra.
1641411475660.png

My question is that what can I do to solve it analytically/algebraically. I used the point-slope formula and obtained $$\frac {y - (a^2-4)} {x - a} = 2a$$, which implies that ##y = (2a)x + (-a^2-4)##.

I am not sure how to proceed from here onwards. Please help me solve this problem. I will see you in about 7 and a half hours.
 
Physics news on Phys.org
That gives you the equation of a line tangent to the parabola for ##x=a##. (Check your work. You made a sign mistake.) Now you need to use the fact that you only want the lines that also pass through the point (3,1). That will allow you to determine which specific values of ##a## work.
 
vela said:
That gives you the equation of a line tangent to the parabola at any point. (Check your work. You made a sign mistake.) Now you need to use the fact that you only want the lines that pass through the point (3,1). That will allow you to determine which specific values of ##a## work.
I see, I got the required points and the question is solved. Thank you.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top