Solving for the Centre of Mass in an Astronaut Space Walk

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Homework Help Overview

The problem involves two astronauts in a space walk, connected by a rope, and examines the movement of their center of mass as one astronaut reels in the rope. The context is centered around concepts of forces, motion, and the center of mass in an isolated system.

Discussion Character

  • Conceptual clarification, Assumption checking, Exploratory

Approaches and Questions Raised

  • Participants explore whether the force exerted by astronaut A while pulling the rope is considered internal or external. There is discussion about the implications of internal forces on the motion of the center of mass.

Discussion Status

Participants are actively questioning the nature of forces in the system and their effects on the center of mass. Some guidance has been provided regarding the cancellation of internal forces, but there is no explicit consensus on the final answer to the problem.

Contextual Notes

There is an emphasis on the need for participants to demonstrate their understanding and efforts before receiving direct answers, in line with forum guidelines.

JenL
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Homework Statement


a) Two astronauts, A of total mass 90kg and B of total mass 110kg are tied together by a light rope 15m long during a space walk. A starts to reel in the rope at her end. After 8.5s she has reduced the length of the rope by 5.5m. What distance does the centre of mass move in this time? Explain your answer.

Homework Equations


x=md/(M+m)

The Attempt at a Solution


a) I thought that because A was pulling the rope the centre of mass would move towards A? As the astronauts are in outer space this is an isolated system but would the pulling of the rope by A be counted as an external force? Or is it an internal force?
 
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JenL said:
a) I thought that because A was pulling the rope the centre of mass would move towards A? As the astronauts are in outer space this is an isolated system but would the pulling of the rope by A be counted as an external force? Or is it an internal force?
It is definitely an internal force, originating inside the system. While A was pulling on the rope, the rope was pulling back :)
 
So if the rope pulls back does that mean it is not moving? Sorry I still do not fully get this
 
JenL said:
So if the rope pulls back does that mean it is not moving?
Indeed. The only way to change the motion of the center of mass of a system is for some external force to act on the system.
 
JenL said:
So if the rope pulls back does that mean it is not moving? Sorry I still do not fully get this
The way to see this is by considering Newton three: action = - reaction.

The center of mass has some coordinate for which (in a simple case)
(m1+ m2) x = m1 x1+ m2 x2
so (m1+ m2) v = m1 v1+ m2 v2
and (m1+ m2) a = m1 a1+ m2 a2
and with Newton two (F = ma), F21 the force by m2 on m1 and F12 the force by m1 on m2:
(m1+ m2) a = F21 + F12 which, according to Newton three is zero !

In short: internal forces cancel for the equations of motion of the center of mass. Cute, isn't it ?
 
So what is the answer ?
 
Nirrjhhar said:
So what is the answer ?
Hi Nirrjhhar, Welcome to PF.

Sorry, but we don't hand out homework results here. You have to show your effort at a solution, then we can point out where its right or wrong, offer advice and other help so that you can solve the problem yourself. See the forum guidelines for more information.
 

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