Solving for the number of periods in this question

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Homework Help Overview

The original poster is working with an equation involving exponential growth, specifically trying to solve for the number of periods required for a value to grow from 1 to 1.21. The equation presented is (1 + (0.2/x))^x = 1.21, where x represents the number of periods.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts various algebraic manipulations, including rooting the expression and using exponential and logarithmic functions, but finds difficulty in isolating x. Some participants note the lack of a proper analytic solution and suggest numeric approximations instead.

Discussion Status

Participants have provided guidance on the nature of the equation, indicating that numeric methods may be necessary. Suggestions include using Newton's method for approximations and tools like WolframAlpha for specific solutions. There is acknowledgment of an exact integer solution for this particular case.

Contextual Notes

Some participants question the original poster's understanding of the methods for obtaining numeric approximations and seek clarification on resources for further information.

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Homework Statement



I hope everyone is having a great day. The equation I am working with at the moment is:

(1+ (.2/x))^(x) = 1.21.

1.21 represents the final value, whereas 1 is the present value. I am trying to solve for x, which represents the number of periods necessary for the entity to grow from 1 to 1.21. I am a little stuck on the algebraic manipulations. If anyone could help that would be awesome, thanks!

Homework Equations

The Attempt at a Solution


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I have attempted rooting the entire expression, as well as using the "e" and "ln" functions, but I am still having trouble isolating x.
 
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There is no proper analytic solution to this type of equation.
You can get numeric approximations to arbitrary precision.
 
mfb said:
There is no proper analytic solution to this type of equation.
You can get numeric approximations to arbitrary precision.

Thank you for clarifying that, as I was pretty confused! Could you tell me where I could find my information on how to do that? Thanks again.
 
"that" means getting numerical approximations? There are many methods, Wikipedia has a long article as usual. Newton's method is the easiest one that works reasonably well in most cases.

If you are just interested in a solution for this specific equation, you can guess some numbers, or use WolframAlpha to find solutions. In this case, the integer solution is exact.
 
mfb said:
... In this case, the integer solution is exact.
@qqpenguin12,

Notice that (1.1)2 = 1.21
 

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