Solving for Total Work: A Monatomic Gas at 27degrees C

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SUMMARY

The discussion focuses on calculating the total work done by a monatomic gas during two thermodynamic processes: a constant volume process from A to B and a constant pressure process from B to C at 27 degrees Celsius. It is established that no work is done during the constant volume process (AB), while the work done during the constant pressure process (BC) can be calculated as the area of a rectangle formed by pressure and volume changes. The key takeaway is that the total work is solely derived from the constant pressure process.

PREREQUISITES
  • Understanding of thermodynamic processes, specifically constant volume and constant pressure.
  • Familiarity with the concept of work in thermodynamics, particularly the area under the pressure-volume curve.
  • Knowledge of the properties of monatomic gases and their behavior under different thermodynamic conditions.
  • Basic proficiency in interpreting graphs related to pressure and volume changes.
NEXT STEPS
  • Study the principles of thermodynamics, focusing on the first law and work calculations.
  • Learn how to calculate work done in various thermodynamic processes, including isothermal and adiabatic processes.
  • Explore the ideal gas law and its applications in thermodynamic calculations.
  • Investigate graphical methods for analyzing thermodynamic processes, including the use of pressure-volume diagrams.
USEFUL FOR

Students studying thermodynamics, physics enthusiasts, and anyone interested in understanding the work done by gases in various thermodynamic processes.

ManuelGR
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Homework Statement


A monatomic gas at 27degrees C undergoes a constant volume process from A to B and a constant pressure process from B to C, as shown in the figure below:

Find the total work done during these two processes.

2ibfayh.jpg



Homework Equations


Not sure...


The Attempt at a Solution


I know I have to find the area under the curve, but I'm not sure how I have to relate the ATM's (pressure) to volume.
 
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ManuelGR said:

The Attempt at a Solution


I know I have to find the area under the curve, but I'm not sure how I have to relate the ATM's (pressure) to volume.

Yes, the work done is the area under the curve. For process AB, is any work done? For process BC, the area formed is a rectangle.
 

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