Solving for Unknown Sides in a Right Triangle: Pythagorean Theory Help

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The discussion focuses on applying the Pythagorean theorem to a right triangle with a diagonal of length 4r and two equal sides of length a. The correct formulation is established as (4r)^2 = 2a^2, leading to the conclusion that r = a/√8 or r = a/(2√2). The participants clarify the relationship between the diagonal and the sides, ensuring accurate application of the theorem.

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Hi
if i have a diagonal in a right triangle costing of 4x and let's say the two sides are a (same size).

Is it then correct to write (4r)2=2a2 or is it correct to write
4r2=2a2

If (4r)2=2a2 is correct, is it then correct to say 16r2=2a2 and √(2a2)/16)
 
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I'm really confused with what you're asking. Start again, and slowly, explain what the length of each side is.
 
christian0710 said:
Hi
if i have a diagonal in a right triangle costing of 4x and let's say the two sides are a (same size).
What does "consisting of 4x" mean?

Is it then correct to write (4r)2=2a2 or is it correct to write
4r2=2a2
Where did "r" come from? Is it what you called "x" before?

IF the length of the diagonal is 4r and the two sides have length a, then the Pythagorean theorem says that [itex](4r)^2= a^2+ a^2[/itex] or [itex](4r)^2= 2a^2[/itex].

If (4r)2=2a2 is correct, is it then correct to say 16r2=2a2 and √(2a2)/16)
Yes, [itex](4r)^2= 16r^2= 2a^2[/itex]. I don't know what that last expression is supposed to be but if [itex]16a^2= 2a^2[/itex] then [itex]r^2= 2a^2/16= a^2/8[/itex] and, taking square roots of both sides, [itex]r= a/\sqrt{8}= a/(2\sqrt{2})= a\sqrt{2}/4[/itex].
 

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