Solving for Work in a Hanging Crate System

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SUMMARY

The discussion focuses on solving a physics problem involving a 110-kg crate suspended from an 11.0 m rope, requiring the calculation of forces and work done. The magnitude of the applied force when the crate is at rest is determined to be 579 N. The work done by the weight of the crate is calculated using the formula mg multiplied by the vertical displacement, while the work done by the user is calculated as the applied force multiplied by the horizontal displacement of 5.2 m. The participant successfully solved part (a) and received assistance for parts (b) and (c).

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Homework Statement



A 110-kg crate hangs from the end of a 11.0 m long rope. You pull horizontally with a varying force to move it a distance d = 5.2 m to the right. (a) What is the magnitude of the applied force F when the crate is at rest in its final position? (b) What is the work done by the weight of the crate? (c) What is the work you do on the crate?

HangingCrate.jpg



Homework Equations





The Attempt at a Solution



I was able to solve part (a) and find the magnitude of the applied force when the crate is at rest in its final position to be 5.79×10^2 N. However, I am not sure how to solve for parts (b) and (c). Any help or suggestions would be greatly appreciated. Thanks.
 
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In (b) work done by weight is mg*vertical displacement of the crate.
In (c) work done by you is F*horizontal displacement of the crate.
 
I got it correct. Thanks for all your help.
 

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