Solving Force of 17g Bullet Accelerated in Rifle Barrel

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Homework Help Overview

The problem involves a 17 g bullet being accelerated in a rifle barrel that is 103 cm long, reaching a speed of 392 m/s. Participants are tasked with using the work-energy theorem to find the average force exerted on the bullet during its acceleration.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss starting with the work-energy theorem and express uncertainty about how to apply it. There is a focus on identifying initial and final velocities and the need to understand the definition of work in relation to force and displacement.

Discussion Status

The discussion is ongoing, with participants exploring the application of the work-energy theorem and clarifying the relationship between work, force, and distance. Some guidance has been provided regarding the initial and final velocities, as well as the definition of work.

Contextual Notes

Participants express confusion about which values to use in their calculations and the definitions involved in the work-energy theorem. There is an emphasis on understanding the concepts rather than moving directly to calculations.

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Homework Statement



A 17 g bullet is accelerated in a rifle barrel
103 cm long to a speed of 392 m/s.
Use the work-energy theorem to find the
average force exerted on the bullet while it is
being accelerated.
Answer in units of N.


Homework Equations





The Attempt at a Solution


No idea how to start this problem
 
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xlogit3k said:
No idea how to start this problem
Why not start with the work-energy theorem?
 
collinsmark said:
Why not start with the work-energy theorem?

Wnet= 1/2mv^2(final)-1/2mv^2(initial)

i don't know what numbers to put in
 
xlogit3k said:
Wnet= 1/2mv^2(final)-1/2mv^2(initial)

i don't know what numbers to put in
Well, you know the initial velocity is 0 and the final velocity is 392 m/s.

But there is also something else you'll need. What is the very definition of work? (Hint: it's a function of force and displacement).
 
collinsmark said:
Well, you know the initial velocity is 0 and the final velocity is 392 m/s.

But there is also something else you'll need. What is the very definition of work? (Hint: it's a function of force and displacement).

force x distance
 
xlogit3k said:
force x distance
That's right! (Well, technically it's the dot product of force and displacement). Now you should have enough to solve the problem.
 

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