Solving Height Above Water Homework: 79kg Person Jumping 100m

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SUMMARY

A 79kg individual jumps from a 100m platform attached to a bungee cord with a spring constant of 40 N/m and a length of 35m. At maximum elongation of the bungee cord, the gravitational potential energy (Ep = mgh) of the jumper is fully converted into the spring potential energy (Ek = 1/2kx²). The jumper's height above the water at this point can be calculated using energy conservation principles, confirming that the bungee cord's maximum elongation occurs when the jumper's downward motion ceases and upward motion begins.

PREREQUISITES
  • Understanding of gravitational potential energy (Ep = mgh)
  • Familiarity with spring potential energy (Ek = 1/2kx²)
  • Basic knowledge of Newton's second law (F = ma)
  • Concept of energy conservation in mechanical systems
NEXT STEPS
  • Calculate the maximum elongation of the bungee cord using energy conservation principles.
  • Explore the effects of varying the spring constant on bungee jump dynamics.
  • Investigate the role of mass in energy conversion during bungee jumping.
  • Learn about the physics of oscillatory motion in bungee jumping scenarios.
USEFUL FOR

Physics students, educators, and anyone interested in understanding the mechanics of bungee jumping and energy conservation principles.

~Sam~
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Homework Statement



79kg person jumps from a platform that is 100m above the water. He is attached by a bungee chord with sprint constant 40 N/m and length 35 m. Now he jumps off. How far is he above the water now when the chord has reached maximum elongation

Homework Equations




F=ma, Ek= 1/2mv2 Ep=mgh...etc

The Attempt at a Solution



I'm kind of stuck.. I know it involves energy, but the maximum elongation of the chord confuses me.
 
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All that it means is that the person is no longer falling and is just about to begin moving upward. In other words, the bunjee jumpers gravitational potential energy has been fully converted into the spring potential energy.
 

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