Solving Laguerre DEby translating it into an Euler equation

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SUMMARY

The discussion focuses on solving the differential equation x y'' -(4+x)y'+2y=0 by translating it into an Euler equation. The indicial equation derived is r(r-5), with roots at r=5 and r=0, where the latter corresponds to Laguerre polynomials. The solution approach involves substituting the power series ansatz y = Σ a_n x^n into the equation, leading to a recurrence relation a_{n+1} ∝ (n-2) a_n, indicating that all coefficients a_n for n > 2 are zero.

PREREQUISITES
  • Understanding of differential equations, specifically second-order linear equations.
  • Familiarity with power series solutions and their convergence.
  • Knowledge of Laguerre polynomials and their properties.
  • Experience with recurrence relations in mathematical analysis.
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  • Study the properties and applications of Laguerre polynomials in mathematical physics.
  • Learn about the method of Frobenius for solving differential equations near singular points.
  • Explore the derivation and implications of the indicial equation in the context of differential equations.
  • Investigate the relationship between power series solutions and special functions in applied mathematics.
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Students and researchers in mathematics, particularly those focusing on differential equations and special functions, as well as educators teaching advanced calculus or mathematical methods for physics.

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Homework Statement



Find the indicial equation and all power series solutions around 0 of the form
xr Ʃan xn for:
x y'' -(4+x)y'+2y=0
- apparently one of these solutions is a laguerre pilynomial

Homework Equations


the indicial equation is the roots of
r(r-1) +p0r+q0
where p0=lim(x->0)( x(-4-x)/x)=-4
and q0=lim(x->0)( x^2 *2/x)=0
Hence the indicial equation is:
r^2-r - 4r =r(r-5)

The Attempt at a Solution


I have a solution for the root at r=5, but I'm not sure how to do it for r=0, which is the Laguerre one...?
 
Last edited:
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What is the difficulty here? Just plug your ansatz [itex]y = \sum_n a_n x^n[/itex] into the equation, and solve like usual. By googling "laguerre polynomial" you will see that you expect to get a solution which contains only 2+1 = 3 terms; you will probably find something like [itex]a_{n+1} \propto (n-2) a_n[/itex], meaning that for all n>2, an = 0.
 

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