Solving LC Circuits: Time Interval Between Max Current & Voltage

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The discussion revolves around calculating the time interval between maximum current in an LC circuit and maximum voltage across the capacitor. The total energy stored is given as 2J, with inductance of 10^-2 H and capacitance of 100 μF. The equations T = 2∏/ω and ω = √(1/LC) are used to find the period T, but confusion arises regarding the need to divide T by 4 to find the required time interval. Clarification is provided that this division relates to the phase difference between current and voltage in the circuit, with maximum current occurring a quarter period before maximum voltage. The conversation emphasizes understanding the relationship between current and voltage in resonant LC circuits, highlighting the 90-degree phase shift.
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Homework Statement


The total energy stored in an LC circuit is 2J. The inductance is 10^-2 H and the capacitance is 100 μF. What is the time interval between a maximum current through the inductor and a maximum potential difference in the capacitor?

Homework Equations


T = 2∏/ω
ω = √(1/LC)

The Attempt at a Solution



I understand how the two above equations can be used to find T. However, in the answer key I have, it requires you to take the T you get and divide by 4 to find the time. I don't understand where this step comes in.

Also, is it possible to solve this question using the equation that tells us the charge on a capacitor (q = QV - e^(-t/RC)). I initially tried setting this up to find t when q = 0 and t when q = Q. However, is this not possible because we do know know and cannot find R? Or is there some other reason why using this equation won't work? Thanks!
 
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It is a resonant LC circuit,without resistance. A similar equation you wrote (q = QV - e^(t/RC), which is not correct at all) would hold for a capacitor and resistor.
The current in the LC circuit changes with time as Imax sin (ωt), the voltage is U=±Umax cos(ωt) across any of the inductor and capacitor. The power stored in a capacitor is 1/2 CU2, the same in the inductor is 1/2 L I2. Plot U2 and I2 vs time. How many times during a period you get a maximum of either U2 or I2?

ehild
 
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Oh, I see, thanks. Can you explain why we have to divide by 4 as the final step?
 


I edited my previous post, read it.

ehild
 


Sorry, but this particular subject material is largely over my head. I can't really follow what you suggest I do. Is there another way to look at it? Alternatively, is it always true that one period includes 4 cycles, such that you always divide the period by 4 to find the time it takes to go from greatest charge on the capacitor to largest current? Sorry if I'm being annoying!
 


Why don't you plot U(t) and I(t)? When the current is maximum, the potential difference is zero, as U=LdI/dt. It will be maximum after pi//2 phase difference.

ehild
 

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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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