Solving Limit: Cos(xy) - 1 over x^2 y^2

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SUMMARY

The limit of the expression (cos(xy) - 1) / (x^2 y^2) as (x,y) approaches (0,0) can be solved by multiplying the numerator and denominator by (cos(xy) + 1). This transformation leads to the expression -[sin^2(xy)/(xy)^2] * [1/cos(xy) + 1]. The critical step involves recognizing that the limit of sin(u)/u approaches 1 as u approaches 0, allowing the simplification of sin^2(u)/u^2 to also approach 1, effectively eliminating the (xy)^2 denominator in the limit process.

PREREQUISITES
  • Understanding of limits in multivariable calculus
  • Familiarity with trigonometric limits, specifically lim(u -> 0) sin(u)/u
  • Knowledge of L'Hôpital's Rule for evaluating indeterminate forms
  • Basic algebraic manipulation of trigonometric identities
NEXT STEPS
  • Study the application of L'Hôpital's Rule in multivariable limits
  • Explore the Taylor series expansion for cos(xy) around (0,0)
  • Learn about the epsilon-delta definition of limits in calculus
  • Investigate other trigonometric limits and their applications in calculus
USEFUL FOR

Students studying calculus, particularly those focusing on multivariable limits, as well as educators seeking to clarify limit evaluation techniques involving trigonometric functions.

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Homework Statement




question asks:

lim(x,y) -> (0,0)

cos(xy) -1 / [x^2 y^2]


Homework Equations





The Attempt at a Solution



if you multiply the top and bottom by cos(xy) + 1 you get

-[sin^2(xy)/(xy)^2] * [1/cos(xy) + 1]

but in the solution they somehow got rid of the denominator (xy)^2, because if that's there the denominator is still 0. How do you get rid of that?
 
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The limit u->0 sin(u)/u=1. So limit u->0 sin(u)^2/u^2=1. That's what they did with the first term.
 

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