Solving Momentum Collision: Finding Velocity of Sliding Blocks | Homework Help

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SUMMARY

The discussion focuses on calculating the velocity of a small block (35 g) just before it collides with a larger block (90 g) at rest. After the collision, the larger block slides 72 cm to the right before stopping, while the smaller block moves 1.5 m to the left. The coefficient of kinetic friction for the table is 0.42. The solution involves applying the conservation of momentum and energy principles, specifically using the equations for kinetic energy and work done against friction.

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Homework Statement



A small (35 g) block is sliding toward the right along a table when it hits a larger (90g) block that was at rest. After the collision, the large block slides 72 cm to the right before coming to a rest , while the small block bounces off the large block, sliding 1.5 m to the left before stopping. The somewhat rough table has a coefficient of kinetic friction of 0.42. What is the velocity of the small block just before it hits the larger block?

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The Attempt at a Solution



so i have to find the final velocity of the larger block...
which could be .72(.42)(.09)?

then i use the conservation of momentum equation?!
 
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you could consider conservation of energy.

The inital block has energy
[tex]Ke= \frac{1}{2} m v^2[/tex]
where v is its velocity
m is the mass.

The second block has lost all its energy overcoming the friction of the table by the time it comes to rest.

As Work done = force*distance

friction force = mass of object* acceleration due to gravity * friction coefficient

can you solve from there?
 
yes, thanks so much!
 

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