Solving Multivariable Limit: x^2y^2/(x^3+y^3)

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SUMMARY

The limit of the function \(\lim_{(x,y)\rightarrow (0,0)}\frac{x^2y^2}{x^3+y^3}\) does not exist. The discussion emphasizes using the squeeze theorem and multiple path approaches to analyze the limit. Participants noted that the denominator changes sign depending on the quadrant, while the numerator remains positive. A suggested method for further exploration includes using polar coordinates and analyzing paths such as \(y = xa\) to determine when the orders of the numerator and denominator are equal.

PREREQUISITES
  • Understanding of multivariable limits
  • Familiarity with the squeeze theorem
  • Knowledge of polar coordinates
  • Ability to analyze functions through path approaches
NEXT STEPS
  • Study the application of the squeeze theorem in multivariable calculus
  • Learn how to convert Cartesian coordinates to polar coordinates
  • Investigate the behavior of limits along different paths
  • Explore the concept of order of growth in multivariable functions
USEFUL FOR

Students and educators in calculus, particularly those focusing on multivariable limits, as well as mathematicians seeking to deepen their understanding of limit behavior in different coordinate systems.

Yuqing
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Homework Statement


Find the limit of

\lim_{(x,y)\rightarrow (0,0)}\frac{x^2y^2}{x^3+y^3}

Homework Equations


I'd like to solve this in a rather elementary manner, so preferably only using the squeeze theorem or through proving the limit doesn't exist via multiple path approach.


The Attempt at a Solution


I've tried substituting y = mxn in general and I've tried bounding the denominator. All to no avail. All paths I've tried so far lead to 0 but I am still not certain that the limit actually exists.
 
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Yuqing said:
All paths I've tried so far lead to 0 but I am still not certain that the limit actually exists.
Indeed, the limit does not exist. When finding the limits of a multivariate function, it is useful to plot the function, this helps you decide on paths of approach.

However, in this case it is useful to note that the denominator changes sign depending on the quadrant, whilst the numerator does not. :wink:
 
Hootenanny said:
However, in this case it is useful to note that the denominator changes sign depending on the quadrant, whilst the numerator does not. :wink:

How exactly would you suggest I approach this? The biggest problem I have is that the numerator is of higher overall order than the denominator. I cannot find a path which does not take me to 0.
 
Try using polar coordinates.
 
Yuqing said:
How exactly would you suggest I approach this? The biggest problem I have is that the numerator is of higher overall order than the denominator. I cannot find a path which does not take me to 0.
Use a path given by y = xa .

For what power, a, will the orders of the numerator & denominator be equal ?
 

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