Solving Parametric Equations for Tangent Line to Space Curve

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
1 reply · 2K views
Electro
Messages
48
Reaction score
0
Hello everyone,
I found a random question regarding finding the parametric equations for a tangent line to a space curve and I'm striving to solve it, but no results. I consulted the book but there isn't anything similar.

Find the parametric equations for the tangent line to the space curve:
x = ln(t), y = 2*Sqrt(t), z = t^2 at the point (0,2,1)

I would appreciate any suggesstions or hints how to solve it.
Thanks
 
Physics news on Phys.org
The time derivative of [itex]\vec x[/itex] is tangent to the curve. If [itex]\vec v = d\vec x/dt[/itex] then the line you are looking for is given by [itex]\vec x_{tangent} = \vec x_0 + \vec v(t = t_0) (t - t_0)[/itex] where [itex]t_0[/itex] is the time corresponding to the point of interest.