Solving Part c of Repulsive Force Homework Problem

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The discussion focuses on solving part c of a homework problem involving a particle subjected to a repulsive force F = +kx. The general solution for the motion is given as x(t)=C1e^(wt)+C2e^(-wt), with constants determined by initial conditions. For part c, the goal is to find the initial velocity v0 that allows the particle to start at x0 and eventually come to rest at the origin. The approach involves analyzing the velocity as a function of time and determining the condition under which it approaches zero as time increases. The solution was successfully derived by taking the limit, confirming the correct initial velocity.
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Homework Statement


(2) Suppose a particle of mass m is subjected to a repulsive force F = +kx.
(a) What is the general solution for the motion of the system?
(b) If the particle begins with a position x(0) = x0 and with velocity v(0) = v0 at t = 0 what are the values of the constants appearing in the general solution?
(c) There is a solution where the particle starts at x0 and moves toward the origin only to remain
at rest there. What is the initial velocity v0?.

Homework Equations


[/B]

The Attempt at a Solution


So I solved part a) and b) and got (what I believe is the right answer) of
a) x(t)=C1e^(wt)+C2e^(-wt)
b)x(t)=(wx0+v0)e^(wt)/(2w)+(wx0-v0)e^(-wt)/(2w)

for part c, how would I go about solving it? I initiallly thought of equating velocity and position, since they are both equal when the particle is at rest, but I think I should instead somehow incorporate force, since the velocity will have to be negative to combat the positive repulsive force, but I'm uncertain on how to obtain v0.
 
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Find an expression for the velocity as a function of time. Then you want to find at what v0 that expression goes to zero as time becomes very large.
 
Last edited:
awesome. figured it out by taking the limit. thanks!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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