Solving Partial Derivatives with f(x-z)=x+y+z

imana41 · Apr 20, 2011

hi i have a problem for this
if f(x-z)=x+y+z solve

$gif.latex?\frac{\partial%20z}{\partial%20x}-2\frac{\partial%20z}{\partial%20y}.gif$

can i say u=x-z and write F(x,y,z)=x+y+z-f(u) and then

$%20z}{\partial%20x}=-\frac{\frac{\partial%20F}{\partial%20x}}{\frac{\partial%20F}{\partial%20z}}.gif$

$%20z}{\partial%20y}=-\frac{\frac{\partial%20F}{\partial%20y}}{\frac{\partial%20F}{\partial%20z}}.gif$

or this isn't true ? thanks if u help me.

lanedance · Apr 22, 2011

f(x-z)=x+y+z, this doesn't make sense, the way you've written it f is a function of one variable (x-z), but has 3 variables and does not reference the original variable (x-z)

imana41 · Apr 27, 2011

what should i do ?

lanedance · Apr 28, 2011

can you start by trying to write the question exactly as it was written?

HallsofIvy · Apr 29, 2011

For example, are you given that f(x, y, z)= x+ y+ z= 0?

imana41 · May 6, 2011

HallsofIvy said:

For example, are you given that f(x, y, z)= x+ y+ z= 0?

no jus written f(x-z)=x+y+z and f is a function of x and y(x,y are Independent)

Solving Partial Derivatives with f(x-z)=x+y+z

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