Solving Physics Problems: Tension, Speed, and Resistive Force

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The discussion focuses on solving three physics problems related to tension, speed, and resistive force. The first problem involves calculating the tension in a rope pulling a sledge at constant speed, where the key is to resolve the weight into parallel and perpendicular components, noting that no net force indicates no acceleration. The second problem suggests using conservation of energy to find Tarzan's speed at the bottom of his swing, considering both potential and kinetic energy. The third problem requires calculating the diver's speed upon entering the water and analyzing the forces acting on him to determine the average resistive force. Insights provided emphasize fundamental physics principles to approach each problem effectively.
Raider.
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Good day, ladies and gentlemen. I am a long time board reader (since my high school days) but have not posted in these forums, till now. I initially registered with plans and hopes to enter a career in physics, now I am taking my first formal college level physics course, in the summer after my second year at university, as a student pursuing premedical studies in neurochemistry and physiology. How things have changed!

I am preparing for an exam, and in the course of 60 or so problems in the chapter on Energy, I've run into a couple pickles, problems that, while aren't particularly difficult, are of a nature where i must certainly be missing some sort of pivotal fact, relationship, or plan regarding set-up, as I've simply not been able to solve them satisfactorily. I'd appreciate any insight you bright individuals may be able to provide with these 3 problems. I don't necessarily need them worked out, just ideas as to how get moving and proceed with them. I'd be greatly in your debt, thank you.

1.) A sledge loaded with bricks has a total mass of 18.0 kg and is pulled at constant speed by a rope inclined at 20.0 degrees above the horizontal. The sledge moves a distance of 20.0 m on a horizontal surface. The coefficient of kinetic friction between the sledge and surface is .500
a.) What is the tension in the rope?
b.) How much work is done by the rope on the sledge?
c.) What is the mechanical energy lost due to friction?

I've got a good idea on how to solve parts B and C, but i simply fail to understand how I can determine the tension in the rope from the information given!

2.) Tarzan swings on a 30.0-m-long vine initially inclined at an angle of 37.0 degrees with the vertical. What is his speed at the bottom of the swing
(a) if he starts from rest?
(b) if he pushes off with a speed of 4.00 m/s?

3.)A 70.0 kg diver steps off a 10m tower and drops from rest straight down into the water. If he comes to rest 5.0m beneath the surface, determine the average resistive force exerted on him by the water.Your help is greatly appreciated, thank you!
 
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Hi Raider!

For question 1 a) resolve the sledges weight into two vectors, one parallel and one perpendicular to the plane. Now the question states that the sledge is moving at a constant speed, therefore it is not accelerating, which means there is no net force on the sledge.
For question 2 try and use the principle of conservation of energy, i.e. the sum of tarzan's potential and kinetic energy at any moment is always the same. So take two positions, one when he starts his swing and one when he finishes his swing. For each calculate his potential and kinetic energy.
For question 3, first calculate the speed he hits the water with ( use a kinematic equation ) then try to examine the forces acting on the diver as he enters the water. First there will be his weight and the resisting force opposing his weight. You can now solve this by using Newtons second law.
Hope this helps.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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