Solving projectile motion equations

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Femme_physics
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Solving projectile motion equations...

Trying to understand this equation...

http://img541.imageshack.us/img541/2658/carqk.jpg

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When you get to the end of this equation, there's s^2 and delta t..

That seems like two unknowns to me. How do they both cancel out?
 
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Okay, but why is it in second degree? Why did they need to add ^2 into a unit?
 


Femme_physics said:
Okay, but why is it in second degree? Why did they need to add ^2 into a unit?

Er.. it seems that you appear to not know that units can be squared, or undergo the same operations as a variable.

An acceleration, for example, is [itex]L/T^2[/itex], where L is length, T is time. So since the time dimension is squared, the units is also squared. In SI units, it is [itex]m/s^2[/itex]. If you don't like the square symbol, then write it as [itex]m/ss[/itex]. There, no more squared.

Zz.
 


Ah...a little deeper ponderage after your replies got me to see the logic :) mercy.