Solving Projectile Motion: Find Initial Velocity

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To solve for the initial velocity of a projectile launched at a 30-degree angle, the projectile's height of 15.0m at a horizontal distance of 100.0m must be analyzed. The tangent of the angle formed by the height and distance indicates that the projectile is descending, suggesting a parabolic trajectory. The trajectory function y(x) needs to be established to find the velocity that results in y=15m when x=100m. The initial angle of 30 degrees is crucial for determining the correct initial velocity, which may not have been adequately incorporated in the initial calculations. A thorough review of the projectile motion equations is necessary to ensure accuracy in the solution.
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a cannon is launched @ 30deg angle above the horizontal with an unknown velocity the projectile is observed to hit a vertical wall at a horizontal distance of 100.0m and it hits a height of 15.0m above the ground, find the initial velocity.

the following is what i did to solve it, but the fact that i didnt even use the 30deg at all throughout the solution has me second guessing my solution, so i was wondering if anyone could point out what i did wrong

any help is appreciated

thanks

http://desi.thriceshy.com/images/1440scan.jpg
 
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The height of the wall 15m divided by distance 100 m = 0.15 and tan-1 (0.15) = 8.53°, which means that the projectile is fired above that angle and therefore the projectile must be traveling downward in its parabolic trajectory.

Neglecting air resistance, the trajectory is parabolic, and one must find the function y(x) which describes the parabolic trajectory and find v which gives y=15 m at x=100 m.

Something like this - http://hyperphysics.phy-astr.gsu.edu/Hbase/traj.html#tra8
 
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