Solving r=5sin(2^): What Do the Options Mean?

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Homework Help Overview

The discussion centers around the expression r=5sin(2^) and the interpretation of its options regarding maximum and minimum values. Participants are trying to clarify the meaning of the notation and the implications of the provided options.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are questioning the notation "2^" and its meaning, with some suggesting it might represent degrees. There is confusion about how to determine maximum and minimum values based on the expression provided.

Discussion Status

The discussion is ongoing, with participants seeking clarification on the notation and the implications of the options. Some have offered insights into the nature of sine functions and their maximum and minimum values, but there is no consensus on the interpretation of "2^."

Contextual Notes

There is uncertainty regarding the notation used in the problem, particularly what "2^" signifies. Participants are also grappling with the implications of discussing maximum and minimum values in the context of a specific number versus a function.

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can someone explain what this question means
r=5sin(2^)

options
a. max calue r occurs when sin(2^)=1
b. " " sin*2^)=-1
c. min sin(2^)=0
d. min Sin(2^)=-1
 
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Min Max how to figure what they are ??

can someone explain what this question means
r=5sin(2^)

options
a. max calue r occurs when sin(2^)=1
b. " " sin*2^)=-1
c. min sin(2^)=0
d. min Sin(2^)=-1
 
Your notation is strange. What is 2^? I also have trouble understanding the options.
 


1672978 said:
can someone explain what this question means
r=5sin(2^)

options
a. max calue r occurs when sin(2^)=1
b. " " sin*2^)=-1
c. min sin(2^)=0
d. min Sin(2^)=-1
At first I thought that "^" was "degrees" so that sin(2^) was "sin of 2 degrees" but then 5 sin(2 degrees) is a specific number- it would make no sense to talk about "max" and "min" for a single number. Only an expression or function can have "max" or "min" so- what does "sin(2^)" mean?

If the problem was actually r= 5sin(2^x), that is [itex]r= 5 sin(2^x)[/itex], then just use the fact that the largest possible value of sine is 1 and the smallest possible value is -1.
 

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