Solving r=5sin(2^): What Do the Options Mean?

[1672978]

can someone explain what this question means
r=5sin(2^)

options
a. max calue r occurs when sin(2^)=1
b. " " sin*2^)=-1
c. min sin(2^)=0
d. min Sin(2^)=-1

 

[1672978]

Min Max how to figure what they are ??

can someone explain what this question means
r=5sin(2^)

options
a. max calue r occurs when sin(2^)=1
b. " " sin*2^)=-1
c. min sin(2^)=0
d. min Sin(2^)=-1

 

[mathman]

Your notation is strange. What is 2^? I also have trouble understanding the options.

 

[HallsofIvy]

can someone explain what this question means
r=5sin(2^)

options
a. max calue r occurs when sin(2^)=1
b. " " sin*2^)=-1
c. min sin(2^)=0
d. min Sin(2^)=-1

At first I thought that "^" was "degrees" so that sin(2^) was "sin of 2 degrees" but then 5 sin(2 degrees) is a specific number- it would make no sense to talk about "max" and "min" for a single number. Only an expression or function can have "max" or "min" so- what does "sin(2^)" mean?

If the problem was actually r= 5sin(2^x), that is $r= 5 sin(2^x)$, then just use the fact that the largest possible value of sine is 1 and the smallest possible value is -1.