Solving r=5sin(2^): What Do the Options Mean?

So the largest possible value of r is 5 and the smallest possible value of r is -5. Notice that the options have nothing to do with r. The options are about a number that is related to r- the number is called sin(2^x). To make r 5, sin(2^x) must be 1. To make r -5, sin(2^x) must be -1. Only one of the options matches what we want. In summary, the question is asking for the maximum and minimum values of r, which occur when sin(2^x) is equal to 1 and -1 respectively.
  • #1
1672978
2
0
can someone explain what this question means
r=5sin(2^)

options
a. max calue r occurs when sin(2^)=1
b. " " sin*2^)=-1
c. min sin(2^)=0
d. min Sin(2^)=-1
 
Physics news on Phys.org
  • #2
Min Max how to figure what they are ??

can someone explain what this question means
r=5sin(2^)

options
a. max calue r occurs when sin(2^)=1
b. " " sin*2^)=-1
c. min sin(2^)=0
d. min Sin(2^)=-1
 
  • #3
Your notation is strange. What is 2^? I also have trouble understanding the options.
 
  • #4


1672978 said:
can someone explain what this question means
r=5sin(2^)

options
a. max calue r occurs when sin(2^)=1
b. " " sin*2^)=-1
c. min sin(2^)=0
d. min Sin(2^)=-1
At first I thought that "^" was "degrees" so that sin(2^) was "sin of 2 degrees" but then 5 sin(2 degrees) is a specific number- it would make no sense to talk about "max" and "min" for a single number. Only an expression or function can have "max" or "min" so- what does "sin(2^)" mean?

If the problem was actually r= 5sin(2^x), that is [itex]r= 5 sin(2^x)[/itex], then just use the fact that the largest possible value of sine is 1 and the smallest possible value is -1.
 

1. What is "r=5sin(2^)" and what does it mean?

"r=5sin(2^)" is a mathematical expression that represents a polar equation. The "r" value stands for the distance from the origin, and the "sin(2^)" represents the angle in radians. This equation can be graphed to form a curve known as a polar curve.

2. How do you solve "r=5sin(2^)"?

To solve this equation, you will need to use trigonometric identities and algebraic manipulation. First, you can substitute the "sin(2^)" with its equivalent expression of "2sin(^)cos(^)". Then, you can use the Pythagorean identity to simplify the equation and solve for the "r" value.

3. What are the options in "r=5sin(2^)" and how do they affect the graph?

The options in this equation refer to the values of "r" and "^" (angle) that you can input to create different curves. The "r" value affects the distance of the curve from the origin, while the "^" value affects the shape and orientation of the curve. By changing these options, you can create a variety of polar curves.

4. Can you explain the significance of "r=5sin(2^)" in real-life situations?

This equation may not have a direct real-life application, but it is commonly used in mathematics to understand the relationship between distance and angle. It can also be used to describe the motion of objects in circular or periodic motion.

5. How can I graph "r=5sin(2^)" on a coordinate plane?

To graph this equation, you can use a polar graphing calculator or manually plot points by substituting different values of "r" and "^" into the equation. Then, you can plot these points on a polar coordinate plane and connect them to form the desired curve.

Similar threads

  • Precalculus Mathematics Homework Help
Replies
15
Views
595
  • Precalculus Mathematics Homework Help
Replies
1
Views
815
  • Precalculus Mathematics Homework Help
Replies
2
Views
1K
  • Precalculus Mathematics Homework Help
Replies
1
Views
494
  • Precalculus Mathematics Homework Help
Replies
8
Views
988
  • Precalculus Mathematics Homework Help
Replies
23
Views
1K
  • Precalculus Mathematics Homework Help
Replies
6
Views
2K
  • Precalculus Mathematics Homework Help
Replies
1
Views
960
  • Precalculus Mathematics Homework Help
Replies
4
Views
1K
  • Precalculus Mathematics Homework Help
Replies
2
Views
1K
Back
Top