Solving Sampling Frequencies: Discrete Time Signal & Nyquist Frequency

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SUMMARY

The discussion focuses on the sampling of the continuous-time signal x(t) = 3*sin(1000*pi*t) at a sampling rate of fs = 2000Hz. The Nyquist frequency for this signal is established at 1000Hz, which is twice the original frequency of 500Hz. The discrete time signal x[n] can be derived by evaluating the continuous signal at discrete intervals defined by the sampling rate. Understanding the relationship between sampling frequency and discrete time signals is crucial for accurately reconstructing the original signal.

PREREQUISITES
  • Understanding of continuous-time signals and discrete-time signals
  • Knowledge of Nyquist Theorem and sampling rates
  • Familiarity with sine wave functions and their properties
  • Basic mathematical skills for evaluating functions at discrete intervals
NEXT STEPS
  • Learn about the Nyquist-Shannon Sampling Theorem
  • Explore MATLAB or Python for simulating discrete time signals
  • Study the effects of aliasing in signal processing
  • Investigate the reconstruction of signals from their samples
USEFUL FOR

This discussion is beneficial for students in signal processing, electrical engineering, and anyone interested in understanding the principles of sampling and discrete time signal analysis.

Whoohw
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Homework Statement


x(t) = 3*sin(1000*pi*t)

Suppose that the signal is sampled at a rate of fs = 2000Hz. What is the discrete time signal obtained after sampling (i.e., the signal expressed as a function of sample number n, x[n])

What discrete time frequency, f-hat will the signal x[n] be at if x(t) is sampled at its nyquist frequency?

Homework Equations


From the previous parts of this problem:
Original Frequency in hertz: 500 Hz
Niquist frequency: 1000 Hz


The Attempt at a Solution



I do not understand what a discrete time signal is, and as such, i have no idea what to do for these two steps of the problem.
 
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Whoohw said:

Homework Statement


x(t) = 3*sin(1000*pi*t)

Suppose that the signal is sampled at a rate of fs = 2000Hz. What is the discrete time signal obtained after sampling (i.e., the signal expressed as a function of sample number n, x[n])

What discrete time frequency, f-hat will the signal x[n] be at if x(t) is sampled at its nyquist frequency?

Homework Equations


From the previous parts of this problem:
Original Frequency in hertz: 500 Hz
Niquist frequency: 1000 Hz


The Attempt at a Solution



I do not understand what a discrete time signal is, and as such, i have no idea what to do for these two steps of the problem.

The discrete time signals are just the sample values at each sample time. So if you sample a sine wave twice per cycle, and happen to hit the correct phase to sample the + and - peaks of the waveform, your discrete time samples will alternate +/-1. If you sample at 4 times the period of the sine wave, what are the possible discrete time snapshot values that you can get (there is more than one set, depending on the phase of the sampling, right?)?
 

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