Solving Second Order Differential Equations with Initial Value Problem

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SUMMARY

The discussion focuses on solving a second-order differential equation with an initial value problem (IVP) represented by the equation y(t) = Ce^-t*cos(4t) + Ce^-t*sin(4t). The initial conditions provided are y(0) = 1 and y'(0) = -1. The correct approach involves determining the constants C1 and C2, where C1 is found to be 1. The next step requires calculating the derivative y'(t) and setting y'(0) = -1 to solve for C2.

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Homework Statement


I have got the diff equ problem solved out to

y(t)=Ce^-t*cos4t+Ce^-t*sin4t

Homework Equations


now I have to solve for the IVP and the values are y(0)=1, yprime(0)=-1

The Attempt at a Solution


I believe for the first part I just plug in the y(0)=1 which results in the e^-t dropping out
coming out to be C=1 but I am not 100% on it.

Then I am assuming I take the derivative and solve for the next value.
 
Last edited:
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Are you sure those shouldn't be two different constants, as in y(t) = C1 e-t cos(4t) + C2 e-t sin(4t)

Then, you found that C1 = 1.

Now find y'(x) , then set y'(0) = -1 & solve for C2 .
 

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