Solving Simple Harmonic Motion: Cart Position and Time Comparison

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SUMMARY

The discussion centers on solving the position of an air-track cart oscillating on a spring, described by the equation x(t) = (12.5 cm)cos[(18.0 s-1)t]. Participants seek to determine the time t when the cart first reaches a position of x = 12.2 cm. The equation is set up as 12.2 cm = (12.5 cm)cos[(18.0 s-1)t], leading to the need for isolating t. Clarification on the meaning of s-1 as frequency (f) and its relation to the period (T) is also discussed.

PREREQUISITES
  • Understanding of simple harmonic motion principles
  • Familiarity with trigonometric functions and their properties
  • Knowledge of oscillation frequency and period relationships
  • Ability to manipulate algebraic equations to isolate variables
NEXT STEPS
  • Study the derivation of the cosine function in simple harmonic motion
  • Learn how to apply inverse trigonometric functions to solve for angles
  • Explore the relationship between frequency and period in oscillatory systems
  • Practice solving similar problems involving oscillating systems and time calculations
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Students studying physics, particularly those focusing on mechanics and oscillatory motion, as well as educators seeking to enhance their teaching methods in these topics.

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Homework Statement


The position of a an air-track cart that is oscillating on a spring is given by (12.5cm)cos[(18.0s-1)t].
At what value t after t=0 is the cart first located at x=12.2 cm?

The Attempt at a Solution


12.2 cm = (12.5cm)cos[(18.0s^-1)t].

How do I factor t out?

Thanks
 
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What is s?
 
I believe s^-1 is f which is equivalent to 1/T. T is period which is not equal to t time. Anyone could help me?
 

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