Solving Steady State-Circuits: Step by Step Example

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Discussion Overview

The discussion revolves around solving a specific equation related to current in an RL series circuit, particularly focusing on the correct interpretation and application of the equation. Participants seek clarification on the mathematical aspects of the equation and its components.

Discussion Character

  • Homework-related
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant presents the equation I = V/R * (1 - e^t*R/L) but expresses confusion about the bracketed part.
  • Another participant corrects the equation to I(t)=V/R * [1-e^(-t*R/L)], noting a sign change and explaining the meaning of exponentiation.
  • A participant seeks clarification on the interpretation of the exponential term, asking if it means (-e) raised to the power of -t*R/L.
  • Further clarification is provided on the exponential function, emphasizing the need to understand how to calculate it.
  • One participant expresses frustration with their physics teacher's approach and acknowledges their struggle with the math involved.
  • Another participant suggests that if someone is struggling with the calculation, it may indicate a need to improve their math skills, while offering to help check results.
  • A later reply indicates that the original poster has made progress in understanding the equation after reviewing their materials.

Areas of Agreement / Disagreement

There is no consensus on the understanding of the equation and its components, as participants express varying levels of comprehension and correction of the initial equation. The discussion remains unresolved regarding the clarity of the mathematical concepts involved.

Contextual Notes

Participants mention confusion regarding the exponential function and its calculation, indicating a potential gap in foundational math skills necessary for understanding the physics concepts being discussed.

rafterman
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This is a simple question. I know the equation I am supposed to use but I can not get my head around one part. The part in brackets! I keep getting wild numbers as my answer

The equation is :-

I = V/R * (1 - e^t*R/L)

can I ask someone to give me a step by step example of how you place the relevant numbers into it.

V=6
R=10
L= 1 x 10 -4 H
t=1.0 x 10-5 s
e=2.72 (3sf)
 
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The equation describes how current changes with time in a RL series circuit fed by a battery V.
However, there is a mistake, the equation should read:

I(t)=V/R * [1-e^(-t*R/L)] (note the sign change)

My guess is that you don't understand the meaning of e^. In computer jargon ^ stands for exponentiation. Now you shouldn't have problems with this equation.
 
Hi

So are you saying that [1-e^(-t*R/L)] just means (-e) -2.72 to the power of the total -t*R/L
 
[tex]I(t) = \frac V R (1-e^{-\frac{tR}{L}})[/tex]
 
Hi Borak

I know that's the equation I need, but the part in brackets is confusing me. I am not sure I am utilising it correctly.

My book has the equation but no examples of it workings, so I can not see how the bracket part can be substituted for the numbers I have worked out.
 
[tex]e^{-\frac{tR}{L}}[/tex]

is an exponential function, e to

[tex]-\frac{tR}{L}[/tex]

power. If you don't know what that means and how to calculate it, you should quickly get back to your math books.
 
Yeah, I guess...my physics teacher just says read the books instead of him teaching it.

Thanks anyway.
 
Don't get me wrong. What I am aiming at is that it is a simple calculation - if you have a problem with it it means your math skills are way too low for things you are expected to do. We can help you checking if your result is OK, we can point you to the fact exponential function exists, but it is up to you to learn about it.
 
Borek

Honestly thanks, I am struggling slightly because I am playing catch up. Be away from school for a long while due to injury. I have re-read my books and eventually figured it out, some of the numbers I was getting originally as the answer were just not looking right, I really started to confuse myself.

Thanks again
 

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