Solving Tennis Physics: Force & Acceleration

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SUMMARY

The discussion focuses on calculating the acceleration of a tennis ball after being hit by a racket, along with the force exerted during the collision. Using Newton's second law (F = m*a), the acceleration of the tennis ball is determined to be 45.4 m/s² when a force of 5000 N is applied. The force exerted by the tennis ball on the racket is -5000 N, indicating an equal and opposite reaction. The acceleration of the racket is calculated to be -5.3 m/s², demonstrating the interaction between the two objects during the collision.

PREREQUISITES
  • Understanding of Newton's second law (F = m*a)
  • Basic knowledge of unit conversion (grams to kilograms)
  • Familiarity with vector quantities in physics
  • Concept of momentum (p = mv)
NEXT STEPS
  • Study the principles of momentum and its relation to force and acceleration
  • Learn about vector addition and subtraction in physics
  • Explore advanced applications of Newton's laws in collision scenarios
  • Investigate the effects of mass and force on acceleration in different contexts
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and dynamics, as well as educators seeking to clarify concepts related to force, acceleration, and momentum in collision scenarios.

Meowserkitty
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Homework Statement



A tennis racket (950 g) hits a tennis ball (110 g) with a force of 5000 N. What is the acceleration of the tennis ball? During the collision, with what force does the tennis ball hit the tennis racket? What is the acceleration of the tennis racket? (Remember that force and acceleration are vectors, so be careful with positive and negative signs. Assume the player let's go of the racket just after contact.)

Homework Equations




f = m*a

The Attempt at a Solution


5000=110a
a) 45.4 m/s2
b) -5000 N
c) 5000=950a
-5.3 m/s2
 
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Hi Meowserkitty
Be careful with your units, 1N=1Kg/s²
 
oli4 said:
Hi Meowserkitty
Be careful with your units, 1N=1Kg/s²

Nope, 1N=(1kg(m))/s2
Also, whenever you see collisons, that just begs momentum. (p=mv)
Your answer was way too simplistic. Physics is (almost) never that easy, unfortunately.
 
Ah yes, sorry I forgot the m because I was looking at putting the bold tag around Kg first :)
 
Could you explain how I should go about this? Our physics teacher was gone all week and could not help us.
 
You just have to transform the mass expressed in g as expressed in Kg, that is, you divide it by 1000 :)
 
oli4 said:
You just have to transform the mass expressed in g as expressed in Kg, that is, you divide it by 1000 :)
Other than that do I do the same thing I did? And would the rackets acceleration be negative?
 
runningninja said:
Nope, 1N=(1kg(m))/s2
Also, whenever you see collisons, that just begs momentum. (p=mv)
Your answer was way too simplistic. Physics is (almost) never that easy, unfortunately.

We are not doing momentum yet
 
Meowserkitty said:
We are not doing momentum yet
Yes, you are :)
Maybe you didn't call it this way in class, but the Newton's law you are using is
"the force is the rate of change of momentum"
F=d(mv)/dt
As far as you are/will be concerned for a while, mass is constant, so that becomes
F=mdv/dt=ma :)
 

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