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This is my first post...is there a way to add a picture from my own computer to a post?
similar to this problem but with different numbers
In my problem, C=T3, B=T2, and A=T1. The angle on the left is 30 and the one on the right is 45
[tex] \vec{F}_{net} = \Sigma \vec{F} = m \vec{a}[/tex]
What I know...
1. T_c=w
2. T_a sin 30 + T_b sin 45 = w
3. T_a cos 30 - T_b cos 45 = 0
4. sin 45 = cos 45
T_a sin 30 + T_b sin 45 = w
T_a sin 30 + T_b cos 45 = w
becuse of # 3 above, I get
T_a sin 30 + T_a cos 30 = w
T_a(sin 30 + cos 30) = w
T_a(1.366) = w
...I'm stuck here. Please help direct me to find T_a in terms of W. As shown above I came up with "T_a=w/1.366" but the book came up with "T_a=.732w" Thanks is advance for the help.
Homework Statement
similar to this problem but with different numbers
In my problem, C=T3, B=T2, and A=T1. The angle on the left is 30 and the one on the right is 45
Homework Equations
[tex] \vec{F}_{net} = \Sigma \vec{F} = m \vec{a}[/tex]
The Attempt at a Solution
What I know...
1. T_c=w
2. T_a sin 30 + T_b sin 45 = w
3. T_a cos 30 - T_b cos 45 = 0
4. sin 45 = cos 45
T_a sin 30 + T_b sin 45 = w
T_a sin 30 + T_b cos 45 = w
becuse of # 3 above, I get
T_a sin 30 + T_a cos 30 = w
T_a(sin 30 + cos 30) = w
T_a(1.366) = w
...I'm stuck here. Please help direct me to find T_a in terms of W. As shown above I came up with "T_a=w/1.366" but the book came up with "T_a=.732w" Thanks is advance for the help.
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… they're the same!