Hello! I have a question about the following problem:
Two point masses m1 and m2 are attached to isolating wires to point P. They are both positively charges (charge Q1 and Q2) and in the picture you can see the situation at equilibrium.
What is the proportion of the masses (m1 / m2)?[/B]
The Attempt at a Solution
So this is how I would do it:
We have the weight force for m1 which is W1 = m1 * g and for m2 we have W2 = m2 * g
The forces W are is in y-direction
For other forces of the y-direction we have to break down the tension force into its x and y components.
For m1 we can say that the tension force in y direction is T1y = T1 * cos (60°) and for m2 the tension force in y direction is T2y = T2 * cos(30°)
this means that T1 * cos (60°) - m1 * g = 0
and T2 * cos (30°) - m2 g )= 0
or T1 * cos (60°) = m1 * g
and T2 * cos (30°) = m2 * g
If we devide the both equations we get
T1 / T2 * cos(60°) / cos(30°) = m1 / m2
for cos(60) = 1/2
for cos (30) = sqrt (3) /2
cos(60)/cos(30) = 1/sqrt(3)
which leads us to T1 / T2 * 1/sqrt(3) = m1/m2
how can I get rid of T1/T2 and what is m1/m2?
Thanks for your help!
10.6 KB Views: 277