Solving the Frequency of Sound Waves at 20°C

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Homework Help Overview

The discussion revolves around determining the frequency of sound waves based on observations made by a girl walking towards a brick wall. The problem is situated within the context of wave behavior and sound propagation at a temperature of 20°C.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants explore the relationship between sound intensity and distance, with one attempting to apply the universal wave equation. Questions arise regarding the correct interpretation of wave behavior, particularly in relation to standing waves and the nature of reflections from the wall.

Discussion Status

Some participants have provided guidance on visualizing the problem through diagrams, while others have shared insights about wave characteristics. There is an indication that multiple interpretations of the problem are being explored, particularly concerning the nature of the waves involved.

Contextual Notes

Participants are navigating assumptions about wave behavior, including the fixed nature of the wall and the implications for node placement in standing waves. There is also a mention of the terminology used in the thread title, suggesting a need for clarity in the problem's framing.

samisoccer9
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1. a source of sound is directed a large brick wall. a girl walks towards the wall and notices that the intensity of the sound decreases to aminimum every 50cm. what is the frequency of the sound? the air temperature is 20 degrees celsius (answer is 344Hz)2. attempted to use the universal wave equation, being V = frequency x lambda3. found new velocity of sound to be 343.2m/s by doing 331.4 m/s (0.59)(20degrees celsius)
took this new velocity, and attempted to put it into the above listed equation in #2, although the equation is meant for the velocity of a WAVE, i did not know which equation to use. help please and thanks !?
 
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Hi samisoccer9. Have you drawn a diagram showing the incident and reflected waves? Please attach it here.

BTW, the title of your post would be better as INTERFERENCE OF WAVES, not RESONANCE.
 
I haven't drawn any diagrams consisting of waves
 
What do you know about reflected waves and standing waves?
 
ive got the answer now , thanks tho
 
Can you post your solution?
 
Well it says EVERY 50CM, so I took that as the distance between nodes as its a standing wave question. I assumed the brick wall to be a fixed - open, so node to node, meaning LAMBDA is equal to 2L. L being 50cm --> (2)(.5) = 1 meter.
plug into universal wave equation v = f x lambda
343.2 = f x lambda
f = v/lamda --> 343.2/1
f = 343.2 Hz
 

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