Solving the Limit of sqrt(x^2-9)/abs(3-x)

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gipc
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I'm sorry for being pathetic but I can't seem to solve anything this days.

[tex]lim sqrt(x^2-9)/abs(3-x) as x->3+[/tex]
 
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Hi gipc! :smile:

You mean limx->3+ √(x2 - 9) / |3 - x| ?

Well x -> 3+ means you only have to consider x > 3, so |3 - x| = x - 3 …

does that help? :smile:​