Solving the Limit of sqrt(x^2-9)/abs(3-x)

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SUMMARY

The limit of the expression sqrt(x^2-9)/abs(3-x) as x approaches 3 from the right (3+) simplifies to sqrt(x^2-9)/(x-3). As x approaches 3 from the right, the absolute value |3-x| becomes (x-3). This transformation is crucial for evaluating the limit correctly, leading to a clearer understanding of the behavior of the function near the point of interest.

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I'm sorry for being pathetic but I can't seem to solve anything this days.

[tex]lim sqrt(x^2-9)/abs(3-x) as x->3+[/tex]
 
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Hi gipc! :smile:

You mean limx->3+ √(x2 - 9) / |3 - x| ?

Well x -> 3+ means you only have to consider x > 3, so |3 - x| = x - 3 …

does that help? :smile:
 

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