Solving the Mystery of Convergence: \sum_{k=2}^{\infy}(\frac{1}{ln(k!)})

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Homework Help Overview

The discussion revolves around determining the convergence or divergence of the series \(\sum_{k=2}^{\infty}(\frac{1}{\ln(k!)})\), focusing on the application of various convergence tests and approximations.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of the d'Alembert ratio test, noting that it yields inconclusive results. Suggestions include exploring Raabe's test and considering Stirling's approximation as potential methods for analysis.

Discussion Status

Participants are actively exploring different convergence tests and approximations. Some guidance has been offered regarding alternative tests, and there is an acknowledgment of the limitations of the d'Alembert ratio test.

Contextual Notes

There is mention of the course curriculum not covering Raabe's test, which may influence the approaches considered. Additionally, the discussion includes references to Stirling's approximation and its potential relevance to the problem.

Emil_
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Homework Statement


I need help to decide if the series below are convergent or divergent.

<br /> \sum_{k=2}^{\infy}(\frac{1}{ln(k!)})<br />

Homework Equations



The Attempt at a Solution


I tried using the d'Alembert ratio test but the ratio is 1 if I calculated it correctly and then nothing can be said about the series.
 
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Thank you. I'll take a look on Raabe's test and see if I can work it out, but I'm pretty sure it could be done by another test since the course I'm taking doesn't teach Raabe's test.
 
have you heard of stirlings approximation?
 
lanedance said:
have you heard of stirlings approximation?

I think my teacher mentioned briefly an exact formula for n!, involving integrals of arctan etc. He said that the formula was rare even though it was derived 100 years ago, but I've not heard of stirlings approximation. However I think I can solve it using stirlings approximation, thank you!
 
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