Solving the Schrodinger Equation Using Substitution Method: Tips and Tricks

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Homework Help Overview

The discussion revolves around solving the Schrödinger equation using the substitution method, specifically focusing on how to express derivatives with respect to different variables. Participants are exploring the challenges of transforming the equation through variable substitution and differentiation techniques.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss various methods for substituting variables and converting derivatives, including the use of implicit differentiation and the chain rule. Questions arise about how to correctly express second derivatives in terms of first derivatives and the implications of constants in these transformations.

Discussion Status

Several participants have offered insights and suggestions for approaching the problem, including recalling elementary calculus formulas and considering the implications of treating derivatives as coefficients. There is an ongoing exploration of the relationships between different derivatives, but no explicit consensus has been reached.

Contextual Notes

Participants are working within the constraints of the original problem and are attempting to clarify their understanding of the differentiation process in the context of the Schrödinger equation. Some are also addressing issues related to the complexity of the second derivative.

v_pino
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I tried simply substituting z and epsilon into the original equation. I managed to get the second term of the left hand side correct but not the first term as I don't know how to turn z into d^2/dz^2. Can you please give me suggestions as to how I can approach this question.

Thanks
 
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You have a d/dz that you've ultimately got to express in terms of d/dx, right? Try thinking back on your elementary calculus formulas, and see if you can find one that allows you to convert a derivative with respect to one variable into a derivative with respect to a different one.
 
The only thing that I can think of is implicit differentiation. But trying that doesn't seem to work. Am I on the right track?
 
Having the [tex]\frac{d}{dz}[/tex] out by itself can sometimes make things confusing. Try expanding out the parentheses so the [tex]\psi[/tex] can stick onto the derivative. Also, for a moment, let's ignore the fact that it's a second derivative, and pretend it's only a first derivative. So we now have

[tex]\frac{d\psi}{dz}[/tex]

We're assuming this matches up to the original problem, so this term must turn into some kind of d/dx. That term just has constants on it, so the translation between one and the other must just be a simple coefficient. So if we call that A, then we have

[tex]\frac{d\psi}{dz}=A\frac{d\psi}{dx}[/tex]

You should now be able to find a calculus rule that tells you how to calculate A.
 
I used the chain rule to get dS/dz = dS/dx * (h/mw)^0.5 . Can I simply square this to get the second derivative?

S = wavefunction

Thanks for the help!
 
Yup. Now that you know the trick, you can back up and do it with the operators, which will make it a little clearer what's going on:

[tex]\frac{d}{dx} = \frac{d}{dz}\frac{dz}{dx}[/tex]
[tex]\frac{d}{dz} = \frac{1}{\frac{dz}{dx}}\frac{d}{dx}[/tex]
[tex]\frac{d^2}{dz^2} = \frac{d}{dz}\frac{d}{dz}[/tex]
[tex]= \left(\frac{1}{\frac{dz}{dx}}\frac{d}{dx}\right)\left(\frac{1}{\frac{dz}{dx}}\frac{d}{dx}\right)[/tex]
[tex]= \left(\frac{1}{\frac{dz}{dx}}\right)^2\frac{d}{dx}\frac{d}{dx}[/tex]
[tex]= \left(\frac{1}{\frac{dz}{dx}}\right)^2\frac{d^2}{dx^2}[/tex]
 

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