Solving the Swing Tension: A 25kg Child's Story

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SUMMARY

The discussion focuses on calculating the tension in the swing's chain for a 25 kg child swinging at a speed of 3.3 m/s on a 3.5 m swing. The forces acting on the child include the tension in the chain and gravitational force. By applying Newton's second law, participants can derive the necessary equations to find the tension required to maintain the child's circular motion at the bottom of the swing.

PREREQUISITES
  • Newton's Second Law of Motion
  • Circular Motion Dynamics
  • Basic Algebra for solving equations
  • Understanding of gravitational force calculations
NEXT STEPS
  • Calculate the gravitational force acting on the child using F = mg
  • Learn about centripetal acceleration and its relation to circular motion
  • Explore tension force calculations in various physical scenarios
  • Review examples of forces in circular motion for deeper understanding
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Students studying physics, educators teaching mechanics, and anyone interested in understanding forces in circular motion.

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Homework Statement


A 25 kg child is swinging on a 3.5 m swing. At the bottom of the swing
the speed of the child is moving at 3.3 m/s. What is the tension on the
swing’s chain to hold the child?


Homework Equations





The Attempt at a Solution


Can you help me i am confused about this.
 
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tnutty said:
A 25 kg child is swinging on a 3.5 m swing. At the bottom of the swing
the speed of the child is moving at 3.3 m/s. What is the tension on the
swing’s chain to hold the child?

Can you help me i am confused about this.

Hi tnutty! :smile:

The child is moving in a circle.

The forces on the child are the tension in the chain and the force of gravity.

Use good ol' Newton's second law to relate these forces to the child's acceleration. :smile:
 

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