Undergrad Solving this Equation that Wolfram Alpha doesn't compute....

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The equation presented for solving, $$ a = x \cdot \left( c \cdot e^{ \frac {1} {d+x \cdot e }} - b \right) $$, is not computable by Wolfram Alpha, prompting the user to seek assistance. Suggestions include using LaTeX for clarity and considering the Lambert W function for similar forms. However, the specific structure of the equation may require approximation or numerical methods instead of a straightforward analytical solution. The discussion emphasizes the need for more context about the equation's origin to provide better assistance. Ultimately, the equation's complexity suggests that standard computational tools may not suffice without additional parameters.
kajakkajak
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Hi I need to solve this equation: $$ a = x \cdot \left( c \cdot e^{ \frac {1} {d+x \cdot e }} - b \right) $$ for x. Unfortunately Wolfram Alpha refused to compute it. Maybe I need a Pro version. Can anyone help me? Thanks!
 
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kajakkajak said:
Hi I need to solve this equation: x*(c*(exp^(1/(d+x*e)))-b)=a for x. Unfortunately Wolfram Alpha refused to compute it. Maybe I need a Pro version. Can anyone help me? Thanks!
Welcome to the PF. :smile:

Is this question for schoolwork? If so, please re-post it in the Homework Help section of the PF, and show your work toward the solution.

If not, can you say where the equation came from? Also, it would help if you would post math questions using LaTeX -- there is a tutorial under INFO, Help at the top of the page. :smile:

EDIT -- I see you edited your post to change the equation to LaTeX form -- Thanks!
 
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Let ##y=\frac{1}{d+ex}## and try to slve for ##y##.
 
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kajakkajak said:
Hi I need to solve this equation: $$ a = x \cdot \left( c \cdot e^{ \frac {1} {d+x \cdot e } - b \right) $$ for x. Unfortunately Wolfram Alpha refused to compute it. Maybe I need a Pro version. Can anyone help me? Thanks!

Is the "e" in "d + x \cdot e" the same "e" in e^{...}?
 
Hmm... an equation of the form

##a=x*e^x##

has a solution with Lambert function:

##x=W(a)##

so I guess the solution is some variation of that theme?
 
fbs7 said:
Hmm... an equation of the form

##a=x*e^x##

has a solution with Lambert function:

##x=W(a)##

so I guess the solution is some variation of that theme?

Unfortunately, that does not seem to work. It looks like either some type of approximation scheme is needed, or else a numerical method when numerical parameter values are given.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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