Solving Torsion Direction Homework Statement

Click For Summary
SUMMARY

The discussion focuses on solving a torsion direction homework problem using the angle of twist formula: Angle of twist = TL/JG. Participants analyze the impact of torque at different points on a rod, specifically at points B and C, and their contributions to the overall angle of twist. The consensus is that torque applied at point C has a greater effect on the angle of twist over segment 12 compared to torque at point B due to its proximity. The conversation emphasizes the importance of understanding external torques and their summation in torsion problems.

PREREQUISITES
  • Understanding of torsion mechanics
  • Familiarity with the angle of twist formula (Angle of twist = TL/JG)
  • Knowledge of torque and its effects on structural elements
  • Basic principles of static equilibrium in mechanics
NEXT STEPS
  • Study the principles of torsion in materials science
  • Learn about the relationship between torque and angle of twist in engineering applications
  • Explore the concept of static equilibrium and its application in torsion problems
  • Review case studies involving torsion in structural engineering
USEFUL FOR

Students studying mechanical engineering, particularly those focusing on mechanics of materials and torsion analysis, as well as educators looking for examples to illustrate torsion concepts in the classroom.

yecko
Gold Member
Messages
275
Reaction score
15

Homework Statement


E036CA6E-3865-4AB4-82DC-094DCCB867D3.jpeg


Homework Equations


Angle of twist = TL/JG

The Attempt at a Solution


T & L is inversely proportional.
But how can i start attempt the question?
I think it this way: like moment=L*F, and torsion torque is like force, angle of twist is similar to moment (as TL are also positively proportional to angle of twist)
For part (1), T at C would play a more important role to the part 12 for being nearer, and T at B would only contribute half as that at C. Both upper and lower end should havr 0.5T with direction same as C.
For part (2), both upper and lower end should have T and upper with same direction as C and lower part with direction same as D.

The model answer is the answer highlighted in res in the picture above. And I don't understand why. Can anyone explain to me? Thanks.
 

Attachments

  • E036CA6E-3865-4AB4-82DC-094DCCB867D3.jpeg
    E036CA6E-3865-4AB4-82DC-094DCCB867D3.jpeg
    25.6 KB · Views: 969
Physics news on Phys.org
They are not asking about angles. Look at the whole rod, to start. Does the fixed end A experience any torque? If so how much? Sum up all of the external torques. What should that sum be equal to in this situation?
 
Last edited:
yecko said:
T at C would play a more important role to the part 12 for being nearer,
I think you are saying that a torque T applied, in isolation, at C would cause a greater strain over 12 than the same torque applied at B. Is that true? What law governs this?
 
  • Like
Likes   Reactions: scottdave

Similar threads

  • · Replies 21 ·
Replies
21
Views
3K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 1 ·
Replies
1
Views
7K
  • · Replies 50 ·
2
Replies
50
Views
6K
Replies
5
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
1
Views
5K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K