Solving Tree Diagram Problem - Exam Missed

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The forum discussion centers on a tree diagram problem related to probability calculations in an exam context. The participant initially proposed the formula (95+8-N)/100000 to determine the probability of being bitten by a pet, where N represents the number of pet owners bitten by both their own and other pets. However, they later reconsidered and suggested that the correct probability should be calculated as 95/103, indicating a misunderstanding of conditional probabilities. This highlights the importance of accurately interpreting the problem's parameters and the relationships between events.

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justinbaker
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ok so what am i doing wrong here? this was the only question i missed on my exam, and its driving me crazy...

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For (b) I'd have put (95+8-N)/100000 where N is the (unspecified) number of pet owners that are bitten by pets that are not their own and also bitten by their own pet.
 
I would have thought he would be after P(Bitten by own pet|Bitten) which would be 87/95
 
Sounds reasonable. But now I think the answer is 95/103.
 
If there are an infinite number of natural numbers, and an infinite number of fractions in between any two natural numbers, and an infinite number of fractions in between any two of those fractions, and an infinite number of fractions in between any two of those fractions, and an infinite number of fractions in between any two of those fractions, and... then that must mean that there are not only infinite infinities, but an infinite number of those infinities. and an infinite number of those...

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