Solving trigonometric equations

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Homework Help Overview

The discussion revolves around solving the trigonometric equation cos(x) = -cos(2x). Participants explore different methods and relationships involving trigonometric functions.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to solve the equation through graphing but finds it challenging. Other participants suggest examining the relationship between angles and using trigonometric identities to reformulate the equation.

Discussion Status

Participants are actively discussing various approaches, including graphical methods and algebraic transformations. Some guidance has been offered regarding trigonometric identities, but there is no explicit consensus on a single method to solve the equation.

Contextual Notes

There is an indication that some participants are looking for a proof or deeper understanding rather than just a solution, which may influence the direction of the discussion.

davidp92
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Homework Statement


How do you solve cosx=-cos2x?


The Attempt at a Solution


I've tried graphing it, but just wasn't able to crack the solutions

Thanks for help!
 
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What is the relation between two angles a and b if cos(a)=-cos(b)? Look at the unit circle.

Or use the formula cos(2x)=cos^(x)-sin^2(x)

hild
 
If you merely want the answer (without proof), type "solve cos(x)=-cos(2x) for x" in wolfram alpha. If you want to figure out the proof, look up the trig formula that let's you express cos(2x) in terms of cos(x). With that substitution, you will have transformed your equation into a quadratic equation, with cos(x) as the unknown, the solution of which is cos(x)=-1 (implying x=-pi) or cos(x)=1/2 (implying x=pi/3 or x=-pi/3). Of course, add any integer multiple of 2pi to these answers to characterize the infinite number of solutions.
 
or use cos(2x) = 2cos2(x) - 1
 

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