Solving Truss Force Problems: Step-by-Step Guide and Example Calculation

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SUMMARY

This discussion focuses on solving truss force problems using equilibrium equations. The key equations utilized include the sum of forces in the x and y directions, as well as moments equating to zero. The tension in the cable is established at 1200 lb, with calculations leading to a horizontal force at point G (Gx) of 1661 lb and a corresponding Ax of -553 lb. The discussion emphasizes the importance of understanding the geometry of the truss to determine forces in each member and the potential for identifying zero-force members.

PREREQUISITES
  • Understanding of static equilibrium principles in mechanics
  • Familiarity with truss analysis and member forces
  • Knowledge of geometry related to angles in truss systems
  • Proficiency in using free-body diagrams for force analysis
NEXT STEPS
  • Study the method of joints in truss analysis
  • Learn about zero-force member identification techniques
  • Explore advanced equilibrium equations for complex truss systems
  • Practice with software tools like AutoCAD or SolidWorks for truss modeling
USEFUL FOR

Engineering students, structural analysts, and professionals involved in mechanical design or civil engineering who are looking to enhance their understanding of truss force calculations and equilibrium analysis.

xzibition8612
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Homework Statement


See attachment.


Homework Equations



Sum of Fx, Fy, and Moments=0

The Attempt at a Solution



A and B are pins, so there is a x and y component at each of these points. Cable has same tension on either side, 1200. Take the moment at A to be zero: (-1200)(12)+(5/13)(1200)(12)+(-12/13)(1200)(7)+Gx(10).

Gx=1661 lb
1661+Ax=1107, Ax=-553 lb so Ax points to the left.

How do I find Ay and Gy? Then how would I find the force in each member? Thanks.
 

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Hi xzibition8612,
All of the points A through G are assumed to be pinned, so all of the straight elements connected to those pinned joints can only be in compression or tension. In other words, the direction of the elements is also the direction of the force, either compression or tension. There can't be any moments applied on any of the pins, just forces in the direction of the elements. So if you found the force on point G in the X direction, then you can easily calculate the force on point G in the Y direction, because the angle that the element that extends between G and F is known from the geometry they give. Just calculate the angle and you find the force on G in the Y direction. The force Gx and Gy should result in the element being in either compression or tension. Does that help?
 
As it happens, you CAN solve this problem without getting the reactions first. It all depends on you isolating an object for which equilibrium statements can be made. Your choice of object will determine whether the problem is solved easily by hand. Can you identify, by inspection, any members that may be carrying a zero force?
 

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