Solving ux + (x/y)uy = 0 Using Characteristics

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The discussion revolves around solving the partial differential equation ux + (x/y)uy = 0 using characteristics, leading to the solution u(x,y) = C for y = ±x and a function f(x² - y²). Two boundary conditions are provided: u(0,y) = cos(y) and u(x=y,y) = y. The first condition allows the derivation of u(x,y) = cos(√(y² - x²)), but the second condition raises uncertainty about how to proceed. It is noted that the problem is not well-posed, as the characteristic y = x indicates that u must be constant along this line, providing no information for other values. The discussion highlights the complexity of applying boundary conditions in this context.
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Hi,

Homework Statement


I have solved ux + (x/y)uy = 0 using characteristics, to obtain
u(x,y)=C (for y=+-x) and f(x2-y2)


Homework Equations





The Attempt at a Solution


I was then given two boundary conditions:
(a) u(x=0,y)=cos(y), which I used to obtain u(x,y) = cos(√(y2-x2))
(b) u(x=y,y)=y
I am not quite sure how to approach this latter and would appreciate some advice.
 
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peripatein said:
Hi,

Homework Statement


I have solved ux + (x/y)uy = 0 using characteristics, to obtain
u(x,y)=C (for y=+-x) and f(x2-y2)


Homework Equations





The Attempt at a Solution


I was then given two boundary conditions:
(a) u(x=0,y)=cos(y), which I used to obtain u(x,y) = cos(√(y2-x2))

(b) u(x=y,y)=y
I am not quite sure how to approach this latter and would appreciate some advice.

The problem is not well-posed: you've shown that y = x is a characteristic, so u must be constant on y = x and the value of u on y = x tells you nothing about the value of u on x^2 - y^2 = \epsilon for any \epsilon \neq 0.
 
Pardon me, I did mean to add that. Indeed, if C=0 then, for y=+-x, u(x,y) = C. Otherwise (C different than zero), u(x,y)=x^2-y^2.
I'd still appreciate your help with my problem :).
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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