Solving Vector Applications: a-b Magnitude & Ball's Height

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SUMMARY

The discussion focuses on solving two vector-related problems: calculating the magnitude of the vector a-b where a=3i-4j and b=4i-3j, and determining the height of a ball thrown at an initial velocity of 26m/s at a 20-degree angle after 1.4 seconds. The magnitude of the vector a-b is computed using the formula sqrt((a1-b1)² + (a2-b2)²). For the ball's height, the vertical component of the initial velocity is calculated, and the motion equation is applied to find the height at the specified time, considering the effects of gravity.

PREREQUISITES
  • Understanding of vector notation and operations (i.e., vector addition and subtraction).
  • Familiarity with the Pythagorean theorem for calculating magnitudes.
  • Knowledge of basic kinematics, including projectile motion and gravitational effects.
  • Ability to resolve vectors into their horizontal and vertical components.
NEXT STEPS
  • Learn how to calculate vector magnitudes using the Pythagorean theorem.
  • Study the principles of projectile motion, including time of flight and maximum height.
  • Explore the effects of gravity on vertical motion in physics.
  • Practice resolving vectors into components for various angles and magnitudes.
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Students studying physics, particularly in mechanics, educators teaching vector mathematics, and anyone interested in understanding projectile motion and vector operations.

Huskies213
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Can anyone explain what to do for these 2 ?

1.) If a=3i-4j, and b=4i-3j, what is the magnitude of the vector a-b?


2.) A boy throws a ball at an initial velocity of 26m/s at an angle of 20 degrees above the horizontal. How high above the projection point is the ball after 1.4 seconds ?
 
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For the vector problem, i,j represent usually represent mutually orthogonal (perpendicular) vectors, e.g. in x,y-directions.

To add two vectors, one adds corresponding components.

let a = a1i + a2j, and b = b1i + b2j, so a + b = (a1+b1)i + (a2+b2)j. The subtraction is just the additive inverse, i.e. replace + with -.

The magnitude of a is just sqrt(a12+a22). Remember the formula for the length of the hypotenuse of a right triangle - Pythagorean theorem.

In question 2, one has to resolve the vector given by "26m/s at an angle of 20 degrees" into horizontal and vertical components. The ball travels vertically with some velocity component, but decelerates due to gravity, reaches a maximum at some time T, and returns to the same initial elevation at time 2T (i.e. T up and T down - neglecting air resistance).

Using the vertical velocity component, one can establish the equation of motion as a function of time to determine where the ball is at 1.4 s. If T (time to max height) < 1.4 s, then the ball is falling back from its maximum altitude.
 

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