Solving Vector Problems: Magnitude of A | Physics & Math Homework

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Homework Help Overview

The problem involves vector addition and subtraction, specifically determining the magnitude of vector A given two equations involving vectors A and B. The context appears to straddle both physics and mathematics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss geometric interpretations and algebraic rearrangements of the given vector equations. Some express uncertainty about the next steps after visualizing the vectors.

Discussion Status

There is an ongoing exploration of different methods to approach the problem. Some participants suggest solving the equations directly, while others propose graphical methods to verify results. No explicit consensus has been reached regarding the final answer.

Contextual Notes

Participants express concerns about potential mistakes in their calculations and interpretations of the vector equations. The discussion reflects a mix of algebraic and geometric reasoning without resolving the problem completely.

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Homework Statement


We got this problem in our Physics lecture but maybe it should be in the math section. Anyway, the problem is:

If [itex]\vec{A}+\vec{B} = 6\hat{i} + \hat{j}[/itex], and if [itex]\vec{A}-\vec{B} = -4\hat{i} + 7\hat{j}[/itex], what is the magnitude of [itex]\vec{A}[/itex]?

A) 3.0
B) 4.1
C) 5.4
D) 5.8
E) 8.2


The Attempt at a Solution



I drew them out, but other than filling in the angles I'm not quite sure what to do next! I'd appreciate any hints on which direction to go

2iu7zfc.jpg
 
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I guess you could do it geometrically. But there is a faster way. Think of your two equations, and how you could rearrange them to get [itex]\vec{A}[/itex]
 
BruceW said:
I guess you could do it geometrically. But there is a faster way. Think of your two equations, and how you could rearrange them to get [itex]\vec{A}[/itex]

Ohh, I didn't think of solving them as equations. The answer is 2i + 8j which = 8.2? :)
 
Not quite. When you add both equations together, you get: 2 [itex]\vec{A}[/itex] = 2i + 8j So you need to divide by 2 to get [itex]\vec{A}[/itex]
 
BruceW said:
Not quite. When you add both equations together, you get: 2 [itex]\vec{A}[/itex] = 2i + 8j So you need to divide by 2 to get [itex]\vec{A}[/itex]

I need to stop making stupid mistakes like that! I see the answer is i + 4j = 4.1 now, thank you
 
yeah, no worries!
 
To check your result graphically, draw a line segment between the tips of the two vectors you've drawn (A+B and A-B). Bisect that line segment and call the midpoint point C. Draw a vector from the origin to point C. That'll be vector A. The line segment from C to the tip of the A+B vector will be vector B. The negative of B is the line segment from C to the tip of the A-B vector. :smile:
 

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