Solving Work Done in Lifting 150ft Cable, 4lb/ft

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SUMMARY

The work done in winding up a 150 ft cable weighing 4 lb/ft is calculated using the integral W = ∫ py dy from 0 to 150. By substituting the density p = 4, the integral simplifies to W = 4∫ ydy, resulting in W = 45000 ft-lb. This calculation explicitly excludes gravitational force from the equation as per the problem's requirements.

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Homework Statement



Find the work done in winding up a 150 ft cable that weighs 4.00 lb/ft. Assume that the weight includes the gravitational force. In order words exclude the gravitational force g in your calculation.

Homework Equations



W = ∫ pgA(y)D from a ft to b
a = area
P = density
g = gravitational
d= lifting distance


The Attempt at a Solution


The question clearly states that g should be excluded from the equation.
W = ∫A(y) (d) from 150 to zero

But I am not sure of my work.
 
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Finally found a solution to the problem.
W= ∫ py dy from 0 to 150
p = 4

W = 4∫ ydy
W = 4[y^2/2]
W = 4 [11250] = 45000

I Think this is the right answer to the problem.
 

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