Some hermitian operators relations

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SUMMARY

This discussion focuses on the formal demonstration of relations involving Hermitian operators in quantum mechanics. Key relations include the properties that the adjoint of an adjoint operator is the original operator, expressed as (A^{\dagger})^{\dagger}=A, and the product of two operators' adjoints, (AB)^{\dagger}=B^{\dagger}A^{\dagger}. Additionally, it is established that if A is Hermitian and invertible, then its inverse A^{-1} is also Hermitian. The user seeks a more formal proof beyond basic definitions and matrix operations.

PREREQUISITES
  • Understanding of Hermitian operators in quantum mechanics
  • Familiarity with operator adjoints and their properties
  • Knowledge of linear algebra, specifically matrix operations
  • Concept of the identity operator, denoted as \mathbb{I}
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  • Study the formal definitions and properties of Hermitian operators
  • Explore the implications of operator adjoints in quantum mechanics
  • Research proofs involving the identity operator \mathbb{I} in operator theory
  • Learn about the spectral theorem as it relates to Hermitian operators
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How can I formally demonstrate this relations with hermitian operators?(A^{\dagger})^{\dagger}=A
(AB)^{\dagger}=B^{\dagger}A^{\dagger}
\langle x|A^{\dagger}y \rangle=\langle y|Ax \rangle ^*
If \ A \ is \ hermitian \ and \ invertible, \ then \ A^{-1} \ is \ hermitian

I've tried to prove them taking the definition of hermitian operator or/and considering matrices while operating, but I want something more formal.

Thanks
 
Last edited:
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how about using
<br /> AA^{-1}= \mathbb{I}<br />
 

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