Sound Wave Intensity/Sound Level

Thread starter threewingedfury
Start date Dec 10, 2006
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SUMMARY

The intensity of sound wave A is 100 times greater than that of sound wave B, resulting in a sound level difference of +20 dB when calculated using the formula 10 log10(I/I0). This calculation confirms that the correct answer to the relative sound level of wave A compared to wave B is indeed +20 dB. The discussion emphasizes the importance of understanding logarithmic relationships in sound intensity measurements.

PREREQUISITES

Understanding of sound intensity and decibel scale
Familiarity with logarithmic calculations
Knowledge of the formula 10 log10(I/I0)
Basic principles of sound waves

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Study the decibel scale and its applications in acoustics
Learn more about logarithmic functions in physics
Explore sound wave properties and their measurement techniques
Investigate the effects of sound intensity on human perception

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Acoustics students, audio engineers, physicists, and anyone interested in sound wave analysis and measurement techniques.

Dec 10, 2006

threewingedfury

The intensity of sound wave A is 100 times that of sound wave B. Relative to wave B the sound level of wave A is:
a. -2 dB
b. +2 dB
c. +10 dB
d. +20 dB
e. +100 db

Using 10logbase10(I/Io) - 10log(100/1) - Would the answer be 20 dB?

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Dec 10, 2006

FredGarvin

Science Advisor

As long as you are calculating the relative intensities, yes. You are correct.

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