How to Calculate Sound Pressure from Displacement Wave?

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SUMMARY

The discussion focuses on calculating sound pressure from a displacement wave in air, characterized by the equation s(x,t)=smaxcos(kx−ωt) with given parameters: density of air (1.2 kg/m³), wave number (k=8.79 rad/m), angular frequency (ω=3021.6 rad/s), and maximum displacement (smax=2.51 x 10-7 m). The sound pressure is derived using the equations ΔPmax=ρvωsmax and ΔP=ΔPmaxsin(kx−ωt). The user expresses confusion regarding the inclusion of velocity in the equations and seeks clarification on relating displacement to pressure.

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Homework Statement


Consider a sound wave in air of density 1.2 kg/m3. The displacement wave has the form s(x,t)=smaxcos(kx-\omegat) where k=8.79rad/m, \omega=3021.6 rad/s and smax=2.51 x 10-7m.
Calculate the sound pressure \DeltaP(x,t) of this wave at x=0.282m and t=0.00137s. Answer in units of Pa.


Homework Equations


\DeltaPmax=\rhov\omegasmax
\DeltaP=\DeltaPmaxsin(kx-\omegat)

The Attempt at a Solution



I have a feeling I'm not using the correct equations because the equations I've found include a velocity, which isn't given, and don't include the displacement function. How do I relate the displacement function to the pressure equations?
 
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The only way I can think to solve this is by using the kinetic theory of an ideal gas to derive pressure based on average velocity. You can review this derivation at http://hyperphysics.phy-astr.gsu.edu/hbase/kinetic/kinthe.html#c3". The important equation is:

\frac{1}{3} \frac{N}{V} m \bar{v}^2

You can calculate velocity from your displacement equation.
 
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