Sound Waves Frequency Calculation Help

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SUMMARY

The discussion focuses on calculating the lowest two possible frequencies of sound waves emitted from a loudspeaker at the origin, with a speed of sound set at 340 m/s. Listeners positioned at (38m, 0m) and (0m, 29m) receive the wave crests simultaneously, despite being at different distances from the source. The wave equations provided are D(x,t)=Asin(kx-wt+φ) and D(y,t)=Asin(kx-wt+φ), which are essential for determining the wave properties. The key to solving the problem lies in understanding the relationship between distance, wave crest separation, and frequency.

PREREQUISITES
  • Understanding of wave equations, specifically D(x,t) and D(y,t).
  • Knowledge of sound wave propagation and spherical wave emission.
  • Familiarity with the concept of frequency and its relationship to wave speed.
  • Basic trigonometry to analyze distances and angles in the context of wave propagation.
NEXT STEPS
  • Study the derivation of wave equations in physics, focusing on sinusoidal functions.
  • Learn about the relationship between wave speed, frequency, and wavelength.
  • Explore spherical wave propagation and its implications in sound wave analysis.
  • Practice problems involving simultaneous wave reception at different distances to solidify understanding.
USEFUL FOR

Students studying physics, particularly those focusing on wave mechanics, as well as educators seeking to enhance their teaching methods in sound wave calculations.

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Homework Statement


A loudspeaker at the origin emits sound waves on a day when the speed of sound is 340 m/s. A crest of the wave simultaneously passes listeners at the coordinates (38m,0m) and (0m,29m). What are the lowest two possible frequencies of the sound?

Homework Equations


D(x,t)=Asin(kx-wt+[tex]\phi[/tex])
D(y,t)=Asin(kx-wt+[tex]\phi[/tex])

The Attempt at a Solution


I do not know where to start with this problem. I received some advice from the TA, but I am still confused.
 
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assume the wave eminates spherically from the speaker

the fact that they are different distances from the speaker means the listeners both hear different crests at the same time...

think about distances...

how apart are crests in the wave...

how far is each listener form the speaker...
 

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