Sound waves (node and antinodes)

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In standing sound waves, air vibrates with maximum amplitude at antinodes and remains at rest at nodes. Despite initial assumptions, sand accumulates at nodes due to the airflow created by the vibrating air, which moves dust particles. This movement is akin to a broom sweeping dust, causing particles to settle at nodes rather than antinodes. A referenced video illustrates this phenomenon, showing where dust particles accumulate. The explanation clarifies the misunderstanding regarding particle displacement in relation to sound wave behavior.
kelvin macks
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Homework Statement



for part a , since we know that the sand particles will vibrate will max amplitude at antinode and the displacement of partcles is 0 at node. then , the sand should heap at antinode . why the solution gives the sand heap at nodes?

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The Attempt at a Solution

 

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The standing sound wave means that the air vibrates with high amplitude at the antinodes, and moves with high speed there. At the nodes, the air is in rest. The air flow takes the dust particles with itself, sets them into motion. It is like the broom sweeping dust or leaves. Watch video, especially from the 10th second. Where do the dust particles (leaves) accumulate? https://www.youtube.com/watch?v=iM_YIMC6Ic4

ehild
 
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ehild said:
The standing sound wave means that the air vibrates with high amplitude at the antinodes, and moves with high speed there. At the nodes, the air is in rest. The air flow takes the dust particles with itself, sets them into motion. It is like the broom sweeping dust or leaves. Watch video, especially from the 10th second. Where do the dust particles (leaves) accumulate? https://www.youtube.com/watch?v=iM_YIMC6Ic4

ehild

ok, can understand it finally.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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