[spacefight mechanics]how to find true anomaly and eccentricity?

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SUMMARY

The discussion focuses on calculating the true anomaly and eccentricity of an Earth satellite's orbit, given a speed of 7 km/s, a flight path angle of 15 degrees, and a radius of 9000 km. The correct approach involves using the equation r=h^2/u(1+ecostheta) and understanding the relationship between the radius and velocity vectors in a non-rotating Earth-centered reference frame. The final results are a true anomaly of 83.35 degrees and an eccentricity of 0.2785. The initial confusion regarding the need for the standard Earth reference frame was clarified, emphasizing the use of a simpler non-rotating frame instead.

PREREQUISITES
  • Understanding of orbital mechanics and satellite dynamics
  • Familiarity with Lagrange coefficients
  • Knowledge of vector cross products in physics
  • Basic proficiency in using Earth-centered reference frames
NEXT STEPS
  • Study the calculation of orbital elements using Lagrange coefficients
  • Learn about the conversion between different reference frames in orbital mechanics
  • Explore the application of the eccentricity vector in orbital analysis
  • Review the derivation and application of the equation r=h^2/u(1+ecostheta)
USEFUL FOR

Aerospace engineers, orbital mechanics students, and satellite mission planners will benefit from this discussion, particularly those involved in calculating satellite trajectories and understanding orbital dynamics.

smalllittle
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Homework Statement


An Earth satellite has a speed of 7km/s and a flight path angle of 15 degree when its radius is 9000km calculate the true anomaly and eccentricity of the orbit.

Homework Equations



r=h^2/u(1+ecostheta)

The Attempt at a Solution


The problem statement just doesn't seem provided enough information. The direction to the solution should deal with lagrange coefficients. Express r and v in the standard Earth refrence frame using flight pitch angle, then transfer them to the perifocal fame.
Then in perifocal fame:
h=r cross v (in perifocal fame)
e=1/u*(r cross v) -r(vector)/r
But i don't know how to find the r and v vectors in the standard Earth ref frame :(
correct me if my approach is incorrect >.>

the answer given is theta=83.35degree, e=0.2785
 
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smalllittle said:

The Attempt at a Solution


The problem statement just doesn't seem provided enough information. The direction to the solution should deal with lagrange coefficients. Express r and v in the standard Earth refrence frame using flight pitch angle, then transfer them to the perifocal fame.
Then in perifocal fame:
h=r cross v (in perifocal fame)
e=1/u*(r cross v) -r(vector)/r
But i don't know how to find the r and v vectors in the standard Earth ref frame :(
correct me if my approach is incorrect >.>

the answer given is theta=83.35degree, e=0.2785
The problem does provide all the information needed. You do not need to find the r and v vectors in "the standard Earth ref frame", just some earth-centered non-rotating reference frame.

BTW, your equation for the eccentricity vector is incorrect.
 

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