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Spaceship taking circular turn

  1. Apr 11, 2006 #1
    I tried using equations useing different methods of solving this problem but no cigar.

    If anyone can help me just to get started that would be grand.


    A spaceship negotiates a circular turn of radius 3890 km at a speed of 33860 km/h.

    (a) What is the magnitude of the angular velocity?
    (b) What is the magnitude of the radial acceleration?
    (c) What is the magnitude of the tangential acceleration?
  2. jcsd
  3. Apr 11, 2006 #2
    First, convert given info to correct units; meters and seconds.
    Second, use your equations for curviliear motion, they are quite basic.
    Third, the answer to c should be obvious, since the problem states that the speed is not changing....
  4. Apr 11, 2006 #3
    what equation would that be, i dont know one thats called curviliear motion equation.

    i know these equations:
    angular position
    angular velcoity - i would guess to use this but theres not rad given.
    angular acceleration
  5. Apr 12, 2006 #4


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    Staff Emeritus
    Science Advisor
    Gold Member

    Angular velocity can also be represented as;

    [tex]\omega = \frac{v}{r}[/tex]

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