# Spaceship taking circular turn

1. Apr 11, 2006

I tried using equations useing different methods of solving this problem but no cigar.

If anyone can help me just to get started that would be grand.

Thanks

A spaceship negotiates a circular turn of radius 3890 km at a speed of 33860 km/h.

(a) What is the magnitude of the angular velocity?
(b) What is the magnitude of the radial acceleration?
m/s2
(c) What is the magnitude of the tangential acceleration?
m/s2

2. Apr 11, 2006

### civil_dude

First, convert given info to correct units; meters and seconds.
Second, use your equations for curviliear motion, they are quite basic.
Third, the answer to c should be obvious, since the problem states that the speed is not changing....

3. Apr 11, 2006

what equation would that be, i dont know one thats called curviliear motion equation.

i know these equations:
angular position
angular velcoity - i would guess to use this but theres not rad given.
angular acceleration

4. Apr 12, 2006

### Hootenanny

Staff Emeritus
Angular velocity can also be represented as;

$$\omega = \frac{v}{r}$$

Regards
-Hoot