How to Calculate Spacing for Bridge Expansion with Linear Expansion Coefficient

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To calculate the spacing needed for bridge expansion due to temperature increase, the formula ΔL = L₀αΔT is used, where L₀ is the original length, α is the linear expansion coefficient, and ΔT is the change in temperature. For a bridge segment of 76 m and a linear expansion coefficient of 1.2 × 10−5(°C)−1, an increase of 69°F (approximately 20.5°C) results in a calculated expansion of 0.0348 m. The final answer, converted to centimeters, is 3.48 cm. The initial confusion arose from not recognizing the required units for the answer. Proper unit conversion is crucial in such calculations.
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Homework Statement



A bridge is made with segments of concrete 76 m long (at the original temperature). If the linear expansion coefficient is 1.2 × 10−5(◦C)−1, how much spacing is needed to allow for expansion for an increase in temperature of 69◦F? Answer in units of cm.

Homework Equations



I don't know, we never did this in lecture, so I lost as to what to do.

The Attempt at a Solution



What formula am I supposed to use?
 
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DrMcDreamy said:

Homework Statement



A bridge is made with segments of concrete 76 m long (at the original temperature). If the linear expansion coefficient is 1.2 × 10−5(◦C)−1, how much spacing is needed to allow for expansion for an increase in temperature of 69◦F? Answer in units of cm.

Homework Equations



I don't know, we never did this in lecture, so I lost as to what to do.

The Attempt at a Solution



What formula am I supposed to use?
For a formula check
http://hyperphysics.phy-astr.gsu.edu/hbase/thermo/thexp.html
 
Thank you!

So it would be:

\DeltaL=Lo\alpha\DeltaT

\DeltaL= (76 m)(1.2 x 10-5)(◦C)-1(20.5◦C+17.7◦C)

\DeltaL=0.0348 m
 
^It came out to be wrong, so what did I do wrong?
 
DrMcDreamy said:
Answer in units of cm.
ΔL=0.0348 m
That's what's wrong.
 
Oh $h*t! 3.48 cm crap I didnt even realize it had asked in cm!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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