Special Relativity -- Dynamics -- Energy

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Homework Help Overview

The discussion revolves around a problem in special relativity and energy dynamics, specifically involving the collision of antihydrogen and hydrogen atoms and the energy produced from their annihilation. The original poster is attempting to calculate how far a car could travel using this energy, given specific parameters.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of the equation E = mc² to determine the energy produced from the annihilation of antihydrogen and hydrogen. There are questions regarding unit conversions and the total mass involved in the calculations.

Discussion Status

The conversation includes attempts to clarify the calculations and unit conversions necessary for solving the problem. Some participants express confusion about the values being used, while others provide guidance on checking assumptions and calculations. There is no clear consensus on the correct approach yet.

Contextual Notes

Participants are working with specific values for mass and the speed of light, and there is an emphasis on ensuring correct unit conversions. The original poster has indicated a known answer, but discrepancies in calculations have led to further questioning and exploration.

Barry Melby
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Homework Statement


Antihydrogen is the only antimatter element that has been produced in the laboratory, albeit just a few atoms at a time. Each antihydrogen atom consists of a positron in orbit around an antiproton and has the same atomic mass as hydrogen. If an antihydrogen atom collides with a hydrogen atom, they annihilate each other and create gamma radiation.

If this energy could be harnessed in a matter-antimatter automobile engine, how far could a car travel on 10 mg each of antihydrogen and hydrogen? At highway speeds, a typical automobile expends about 2.5×10^3 J per meter.

Homework Equations


E = mc^2

The Attempt at a Solution


I know the answer is 9.00 * 10^8 m, but I haven't been able to work out an answer that is even close to this.

I've solved the minimum amount of energy that is released in this process (3.01 * 10^-10 J). I'm not sure if this is relevant, but I solved it if necessary.
 
Last edited:
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Hi Barry:

I think you omitted an important equation: E = mc2.

Hope this helps.

Regards,
Buzz
 
Okay, so if i use E = mc^2 with m = 10 mg then i get 9 * 10^12 J. Where do I go from here?
 
Barry Melby said:
Where do I go from here?
Hi Barry:

Look at the end of 1. Problem Statement. Also be careful about your units.

Regards,
Buzz
 
I realize that you should be able to take E / 2.5 * 10^3 J/m , but this is incorrect.
 
Hi Barry:

What units are you using for c and m?

Regards,
Buzz
 
c: m/s
m: kg
 
Hi Barry:

What values are you using for c and m?

Regards,
Buzz
 
Buzz Bloom said:
Hi Barry:

What values are you using for c and m?

Regards,
Buzz
c: 3.00 * 10^8 m/s
m: 10 * 10^-5 kg
 
  • #10
Hi Barry:

How are you converting 10 mg into kgs?

Regards,
Buzz
 
  • #11
Hi Barry:

Also, what is the TOTAL input mass, hydrogen and anti-hydrogen?

Regards,
Buzz
 
  • #12
Buzz Bloom said:
Hi Barry:

How are you converting 10 mg into kgs?

Regards,
Buzz
This is exactly what I'm doing:

[(20 * 10^-6)(3 * 10^8)^2] / (2.5 * 10^3) = 720000000

which is incorrect.
 
  • #13
i figured it out. thank you.
 
  • #14
Hi Barry:

OK. You get the same answer I do, which is not the same as the answer you say you know is correct: 9.00 * 10^8 m. Where did this "correct" answer come from?

Regards,
Buzz
 
  • #15
Barry Melby said:
i figured it out. thank you.
Hi Barry:

Glad to have been of some help.

Regards,
Buzz
 

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